Im not 100% sure but i think its bromine.
Hope this helps ^_^
No, non-moving objects do not have inertia.
Answer:
Angular acceleration, ![\alpha =20.32\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D20.32%5C%20rad%2Fs%5E2)
Explanation:
It is given that,
Displacement of the rotating wheel, ![\theta=37\ rev=232.47\ radian](https://tex.z-dn.net/?f=%5Ctheta%3D37%5C%20rev%3D232.47%5C%20radian)
Time taken, t = 2.9 s
Initial speed of the wheel, ![\omega_i=0](https://tex.z-dn.net/?f=%5Comega_i%3D0)
Final speed of the wheel, ![\omega_f=97.2\ rad/s](https://tex.z-dn.net/?f=%5Comega_f%3D97.2%5C%20rad%2Fs)
Let
is the angular acceleration of the wheel. Using the third equation of kinematics to find it as :
![\alpha=\dfrac{\omega_f^2-\omega_i^2}{2\theta}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B%5Comega_f%5E2-%5Comega_i%5E2%7D%7B2%5Ctheta%7D)
![\alpha=\dfrac{(97.2)^2}{2\times 232.47}](https://tex.z-dn.net/?f=%5Calpha%3D%5Cdfrac%7B%2897.2%29%5E2%7D%7B2%5Ctimes%20232.47%7D)
![\alpha =20.32\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D20.32%5C%20rad%2Fs%5E2)
So, the angular acceleration of the wheel is
. Hence, this is the required solution.
<span>Answer:
The moments of inertia are listed on p. 223, and a uniform cylinder through its center is:
I = 1/2mr2
so
I = 1/2(4.80 kg)(.0710 m)2 = 0.0120984 kgm2
Since there is a frictional torque of 1.20 Nm, we can use the angular equivalent of F = ma to find the angular deceleration:
t = Ia
-1.20 Nm = (0.0120984 kgm2)a
a = -99.19 rad/s/s
Now we have a kinematics question to solve:
wo = (10,000 Revolutions/Minute)(2p radians/revolution)(1 minute/60 sec) = 1047.2 rad/s
w = 0
a = -99.19 rad/s/s
Let's find the time first:
w = wo + at : wo = 1047.2 rad/s; w = 0 rad/s; a = -99.19 rad/s/s
t = 10.558 s = 10.6 s
And the displacement (Angular)
Now the formula I want to use is only in the formula packet in its linear form, but it works just as well in angular form
s = (u+v)t/2
Which is
q = (wo+w)t/2 : wo = 1047.2 rad/s; w = 0 rad/s; t = 10.558 s
q = (125.7 rad/s+418.9 rad/s)(3.5 s)/2 = 952.9 radians
But the problem wanted revolutions, so let's change the units:
q = (5528.075087 radians)(revolution/2p radians) = 880. revolutions</span>
Answer:
inversion would be going toward or inside internal and eversion is going outside or external