The given equation is 
where h is the height, in feet, of a ball and t is the time, in seconds.
<u>Part a: The height of the ball when t = 2 seconds:</u>
The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation , we get;
Simplifying the terms, we get;
Thus, the height of the ball after 2 seconds is 100 feet.
<u>Part b: The height of the ball when t = 4 seconds:</u>
The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation , we get;
Simplifying the terms, we get;
Thus, the height of the ball after 4 seconds is 68 feet.
Easy, that is the slope from (2,f(2)) to (3,f(3))
remember that the slope between the points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
find f(2) and f(3)
f(2)=2²+6(2)+5=4+12+5=21
f(3)=3²+6(3)+5=9+18+5=32
so the slope from (2,21) to (3,32) is (32-21)/(3-2)=11/1=11
answer is 11
Answer:
the correct anwser is -3 and if you need anymore help the website i use is
Step-by-step explanation:
https://www.tiger-algebra.com
A second degree polynomial function has the general form:
, where
.
The leading coefficient is a, so we have a=-1.
5 is a double root means that :
i) f(5)=0,
ii) the discriminant D is 0, where
.
Substituting x=5, we have
f(5)=a(5)^2+b(5)+c,
and since f(5)=0, and a is -1 we have:
0=-25+5b+c
thus c=25-5b.
By ii)
.
Substituting a with -1 and c with 25-5b we have:
Finally we find c: c=25-5b=25-50=-25
Thus the function is
Remark: It is also possible to solve the problem by considering the form
directly.
In general, if a quadratic function has leading coefficient a, and has a root r of multiplicity 2, then its form is
Answer:
x = 9
Step-by-step explanation:
Subtract 6 from both sides.
Multiply both sides by 3.
Answer: x = 9
