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shtirl [24]
3 years ago
14

Simplify the expression (3x^2y^-3)^3/27(xy)^-9?

Mathematics
2 answers:
egoroff_w [7]3 years ago
5 0
\frac{[(3x^{2}y^{-3})^{3}]}{27(xy)^{-9}}\\\\\frac{27x^{6}y^{-9}}{27x^{-9}y^{-9}}\\\\\frac{27x^{6}}{27x^{-9}}*\frac{x^{9}}{x^{9}}\\\\\frac{x^{15}}{1}\\\\x^{15}

Your answer should be x^{15}.
Serga [27]3 years ago
3 0
Hello here is a solution : 

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Write an equation in slope-intercept form of the line shown.
7nadin3 [17]

Answer:

y = 2x - 5

Step-by-step explanation:

Find the slope using the points, (1, -3) and (3, 1):

slope(m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 -(-3)}{3 - 1} = \frac{4}{2} = 2

m = 2

Find the y-intercept (b) by substituting x = 1, y = -3, and m = 2 in y = mx + b

-3 = (2)(1) + b

-3 = 2 + b

Subtract 2 from both sides

-3 - 2 = 2 + b - 2

-5 = b

b = -5

Plug in the value of m and b into the slope-intercept form equation, y = mx + b.

Thus:

y = 2x +(-5)

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3 years ago
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Iteru [2.4K]

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3 years ago
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3 0
2 years ago
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What is the value of y in the equation 5x + 2y = 20, when x = 0.3?
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3 years ago
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nirvana33 [79]

Answer:

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Step-by-step explanation:

Find the distance between the midpoint, (-3, -1) and (5, 4). This can be calculated by finding the difference between the x coordinates and y coordinates.

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-1 - 4 = -5 (distance between y coordinates)

Find the point (x, y) by subtracting 8 from the midpoint's x value, and then subtracting 5 from the midpoint's y value.

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2 years ago
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