Simplify the expression (3x^2y^-3)^3/27(xy)^-9?

Mathematics

2 answers:

egoroff_w [7]3 years ago

5 0

$\frac{[(3x^{2}y^{-3})^{3}]}{27(xy)^{-9}}\\\\\frac{27x^{6}y^{-9}}{27x^{-9}y^{-9}}\\\\\frac{27x^{6}}{27x^{-9}}*\frac{x^{9}}{x^{9}}\\\\\frac{x^{15}}{1}\\\\x^{15}$

Your answer should be $x^{15}$ .

Serga [27]3 years ago

3 0

Hello here is a solution :

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$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$