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shtirl [24]
3 years ago
14

Simplify the expression (3x^2y^-3)^3/27(xy)^-9?

Mathematics
2 answers:
egoroff_w [7]3 years ago
5 0
\frac{[(3x^{2}y^{-3})^{3}]}{27(xy)^{-9}}\\\\\frac{27x^{6}y^{-9}}{27x^{-9}y^{-9}}\\\\\frac{27x^{6}}{27x^{-9}}*\frac{x^{9}}{x^{9}}\\\\\frac{x^{15}}{1}\\\\x^{15}

Your answer should be x^{15}.
Serga [27]3 years ago
3 0
Hello here is a solution : 

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What is the area of cross-section ADGF of this right rectangular prism?
dedylja [7]

Answer:

C.52 square units

Step-by-step explanation:

We are given that

Length of cross-section ADGF,l=13units

Length of cross-section ADGF, b=4 units

We have to find the area  of cross-section ADGF of this right rectangular prism.

We know that

Area of rectangle=l\times b

Using the formula

Area of cross-section ADGF of this right rectangular prism

=13\times 4

Area of cross-section ADGF of this right rectangular prism=52square units

Option C is correct.

C.52 square units

5 0
2 years ago
Alice, Ben and Carol shared a sum of money they received. Alice received 1/5 of the money. The rest of the money was divided bet
Levart [38]

Answer:

$3

Step-by-step explanation:

The money shared by Ben and Carol was split ...

... Ben : Carol = 1 : 3

The difference of these ratio numbers is 2, and the difference in amount received is $6. Thus, each ratio unit must stand for $6/2 = $3.

... Ben received 1×$3 = $3

_____

<em>The Rest of the Story</em>

Carol received 3×$3 = $9. Together, Ben and Carol received $3 + 9 = $12, which is 4/5 of the total amount. Then the 1/5 of the total amount that Alice received is

... (1/5)×$12/(4/5) = (1/4)×$12 = $3.

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... Alice : Ben : Carol = $3 : $3 : $9

8 0
2 years ago
Help idk what to do help
s2008m [1.1K]

Step-by-step explanation:

hope it helps you!!!!!!!!

4 0
2 years ago
4 employees drive to work in the same car. the workers claim they were late to work because of a flat tire. their managers ask t
Brums [2.3K]

Answer:

The required probability is 0.015625.

Step-by-step explanation:

Consider the provided information.

There number of tires are 4.

The number of workers are 4.

The probability that individual select front drivers side tire = \frac{1}{4}

The probability that they all select front drivers side,tire is: \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}=\frac{1}{256}

Similarly,

The probability that they all select front passenger side, tire is: \frac{1}{256}

The probability that they all select rear driver side,tire is: \frac{1}{256}

The probability that they all select rear passenger side, tire is: \frac{1}{256}

Hence, the probability that all four workers select the same​ tire = \frac{1}{256}+ \frac{1}{256}+\frac{1}{256}+\frac{1}{256}

the probability that all four workers select the same​ tire = \frac{4}{256}=\frac{1}{64}=0.015625

Hence, the required probability is 0.015625.

5 0
3 years ago
What is the fractional equivalent of 225%?
vitfil [10]
You would start out by putting 225 over 100 then simplifying from there. You would end up getting 9/4. As a mixed number that would be 2 and 1/4.
7 0
3 years ago
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