All categories

2 years ago

What will you spend altogether if you got a movie ticket for $5 and popcorn and a water bottle

Mathematics

2 answers:

solmaris [256]2 years ago

5 0

If they are all 5 dollars then it will be $15

valentinak56 [21]2 years ago

4 0

$10………………………………………………….

You might be interested in

[y = 4x] [x + y = 5]

alexandr1967 [171]

X=1, y=4

Substitute 4x in for y in the second equation and you get 5x=5. Divide out 5 and you get x=1. Then, you can plug 1 in for x into either equation and solve for y.

5 0

2 years ago

The equation 3/4 [x-1]=[-3] is equivalent to?

olga nikolaevna [1]

Answer: x= (-3)

Step-by-step explanation:

3/4 [x-1] = [-3]

(x-1) = (-3) × 4/3

X-1 = -4

X= -3

3 0

3 years ago

Which is the graph of the equation y-1=2/3(x-3)

Alexxandr [17]

The attachment is the graph of the equation y - 1 = 2 / 3 (x - 3)

4 0

3 years ago

Write a quadratic equation in factored form to model the given problem. Be sure to write the entire equation.

Veronika [31]

Equation :
[x(x+4)]/2=6 (as (b*h)/2=A)
x*x + 4*x -12 = 0

$x = -b+- \sqrt{ b^{2}-4ac }/2a$

so, x = 2 units(as -6 is negative)

3 0

2 years ago

The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how

vichka [17]

Answer:

The number of bacteria after $8th$ will be $3840$

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

$A=A_0r^{n-1}$

Where $A$ is number of bacteria after $n$ hours.

$A_0$ is bacteria present initially.

$r$ is the common ration, in our problem it is given that bacteria doubles every hour. So, $r=2$

And $n$ is the number of hours. In our problem we need amount of bacteria at the end of $8th$ hours. So, $n=8$

Plugging values in the formula we get,

$A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840$

So, number of bacteria after $8th$ will be $3840$

3 0

2 years ago