Answer:
a. Ca(s) + 2H⁺ → Ca²⁺ + H₂(g)
b. 0.0100 moles Ca; 0.0140 moles HCl.
c. HCl is limiting reactant.
d. 0.0030 moles of Ca
Explanation:
a. In water, HCl dissociates in H⁺ and Cl⁻ and CaCl₂ in Ca²⁺ and 2 Cl⁻. The ionic equation is:
Ca(s) + 2H⁺ + 2Cl⁻ → Ca²⁺ + 2Cl⁻ + H₂(g)
<h3>Ca(s) + 2H⁺ → Ca²⁺ + H₂(g)</h3>
b. Moles Ca -Molar mass 40.1g/mol-:
0.401g * (1mol / 40.1g) = 0.0100 moles Ca
Moles HCl:
0.350L * (0.0400mol / L) = 0.0140 moles HCl
c. In the reaction, 1 mole of Calcium reacts with 2 moles of HCl.
For a complete reaction of 0.0100 moles of Calcium there are necessaries:
0.0100mol Ca * (2 mol HCl / 1 mol Ca) = 0.0200 moles HCl
<em>As there are just 0.0140 moles of HCl,</em>
<em>HCl is limiting reactant</em>
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d. For a complete reaction of 0.0140 moles of HCl, the moles of Ca that react are:
0.0140 moles HCl * (1 mol Ca / 2 mol HCl) = 0.0070 moles Ca
That means will remain:
0.0100 moles - 0.0070 moles:
0.0030 moles of Ca
