2( coin faces) 8( number of times)
Answer:
15.71 ft
Step-by-step explanation:
Given that:
width of the circular track = 2.5ft
Suppose the radius of the inner circle is 57 ft since it is not given
Then the radius of the outer circle = (2.5 + 57) ft = 59.5 ft
The circumference of a circle = 2πr
For inner circle now, the circumference = 2 × π × 57 ft
For inner circle now, the circumference = 358.14 ft
For the outer circle, the circumference = 2 × π × 59.5 ft
For the outer circle, the circumference = 373.85 ft
The difference between the circumference of the outer wheel from the inner wheel shows how farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn
∴
= ( 373.85 - 358.14 ) ft
= 15.71 ft
Answer:−3K−395,−374,−198,−187
Step-by-step explanation:
Remove parentheses.
1−3K−396,0−374,0−198,0−187
Simplify 1-3K-3961−3K−396 to -3K-395−3K−395.
−3K−395,0−374,0−198,0−187
Simplify 0-3740−374 to -374−374.
−3K−395,−374,0−198,0−187
Simplify 0-1980−198 to -198−198.
−3K−395,−374,−198,0−187
Simplify 0-1870−187 to -187−187.
−3K−395,−374,−198,−187
Answer:
314 units²
Step-by-step explanation:
Centre of the circle = (0, 0)
Another point on the circle = (-6, -8)
Area = π (10)² = 100π = 314 units²
Answer: 70
Step-by-step explanation:
a^2 + b^2 = c^2
24^2 + b^2 = 74^2
576 + b^2 = 5,476
-576 -576
b^2 =4,900
(square root)
b =70
