This is a problem in "binomial probability." Either the archer hits his target or he does not. This experiment is performed 5 times (so that n=5), and the probability that the archer will hit the target is 0.7 (so that p=0.7).
We need to find the binomial probability that x=3 when the possible outcomes are {0, 1, 2, 3, 4, 5}.
You could use a table of binomial probabilities to evaluate the following:
P(5, 0.7, 3).
Alternatively, you could use a TI-83 or TI-84 calculator and its built-in "binompdf( " function.
I evaluated binompdf(5,0.7,3) and obtained the result 0.309.
Answer:
The statement that cushion A is twice as popular as cushion B cannot be verified
Step-by-step explanation:
From the question we are told that:
Sample size n=38
Type a size A 
Type a size B
Generally the probability of choosing cushion A P(a) is mathematically given by


Generally the equation for A to be twice as popular as B is mathematically given by

Therefore Hypothesis

Generally the equation normal approx of p value is mathematically given by



Therefore from distribution table


Therefore there is no sufficient evidence to disagree with the Null hypothesis 
Therefore the statement that cushion A is twice as popular as cushion B cannot be verified
Say your test is out of 100 and you 75 correct to calculate your percent you would go
75/100*100
/ = Divide
* = Times
Answer:
b or c
Step-by-step explanation:
2×-1 +1= -1
-1>-3
2×0+1= 1
1>-3
For this reason the equality can be b or c