Answer: A, B, and C are positive constants and that x+y= C. Show that the minimum value of +Ax%5E2%2BBy%5E2+ occurs when .
Step-by-step explanation:
;)
3*4=12
8*4=32
It is a ratio.
Answer: 12.5
You start with the equations "2x +2y=38" and "6+x=y". By adding and subtracting in the second equation, you get "2x +2y=38" and "x-y=-6". When you multiply the second equation by 2, you get "2x-2y=-12."
subtracting the equations "2x +2y=38" and "2x-2y=-12" gets you to "4y=50", where you have to divide two sides by 4 and get "y=12.5"
88(3.7+4.3)-2*2.6
88(8)-2*2.6
704-2*2.6
704-5.2
698.8
I hope it helps!
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