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mrs_skeptik [129]
2 years ago
9

I need help please .

Mathematics
1 answer:
Black_prince [1.1K]2 years ago
3 0

Answer:

-7-6b+3b-5

= -12-3b

= - 3(4+b)

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Rewrite the expression using positive exponents<br> 1. 1/9x^-2y^-1<br><br> 2. a^-5*a^-8
NikAS [45]

Answer:

Property : a^-b = 1/a^b

Using this property, we can rewrite the expression using positive exponents :

1.  \frac{1}{9}*x^{-2} *y^{-1} =\frac{1}{9}\frac{1}{x^{2} } \frac{1}{y} =\frac{1}{9x^{2} y} \\2. a^{-5} a^{-8} =\frac{1}{a^{5}a^{8}  } =\frac{1}{a^{13} }

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2 years ago
Select all the values of x so g(x) is not a function.
alexdok [17]
The answer is 6 and 9
Step-by-step explanation: We are trying to figure out what makes the chart not a function. A function is is one input equals one output.
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7 0
3 years ago
37% of women consider themselves fans of professional baseball. you randomly select six women and ask each if she considers hers
valina [46]

Answer:

(a) 2.22

(b) 1.3986

(c) 1.183

Step-by-step explanation:

Let <em>X</em> denote the number of women who consider themselves fans of professional baseball.

The proportion of women who consider themselves fans of professional baseball is, <em>p</em> = 0.37.

A random sample of <em>n</em> = 6 women are selected and each was asked if she considers herself a fan of professional baseball.

Each woman's reply is independent of the others.

The random variable <em>X</em> thus follows a binomial distribution with parameters <em>n</em> = 6 and <em>p</em> = 0.37.

(a)

Compute the mean of the binomial distribution as follows:

\text{Mean}=np=6\times 0.37=2.22

(b)

Compute the variance of the binomial distribution as follows:

\text{Variance}=np(1-p)=6\times 0.37\times (1-0.37)=1.3986

(c)

Compute the standard deviation of the binomial distribution as follows:

\text{Standard Deviation}=\sqrt{np(1-p)}=\sqrt{6\times 0.37\times (1-0.37)}=1.183

5 0
2 years ago
Math test! i need help!
FrozenT [24]

Answer:

First option

Step-by-step explanation:

Have a nice day

8 0
2 years ago
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