With the help of the given equation, we know that the automobile is worth $12528.15 after four years.
<h3>
What are equations?</h3>
- A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.
- a formula that expresses the connection between two expressions on each side of a sign.
- Typically, it has a single variable and an equal sign.
- Like this: 2x - 4 Equals 2.
- In the above example, the variable x exists.
So, the equation of depreciation: y = A(1 - r)∧t
The current value is y.
A is the initial cost.
r is the depreciation rate.
t is the time in years, and
In four years, we must ascertain the present value.
Now,
y = $24000(1 - 0.15)⁴
y = 24000(0.85)⁴
y = 24000 × 0.52200625
y = 12528.15
Therefore, with the help of the given equation, we know that the automobile is worth $12528.15 after four years.
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Complete question:
The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years. The original value of a car is $24,000. It depreciates 15% annually. What is its value in 4 years? $
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-5a^2 - 7a = -a x (5a + 7)
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Answer:
The average rate will be 2.40 dollars per kg.
Hence, option D is correct.
Step-by-step explanation:
From the table, it is clear that the order size is located on the x-axis and the price is located on the y-axis.
The price of 100 kg cumin = $450
The price of 600 kg cumin = $1650
so
at x₁ = 100, f(x₁) = 450
at x₂ = 600, f(x₂) = 1650
Using the formula to determine the average rate of change at which the total cost increases will be:
Average rate = [f(x₂) - f(x₁)] / [ x₂ - x₁]
= [1650 - 450] / [600-100]
= 1200 / 500
= 2.4
Therefore, the average rate will be 2.40 dollars per kg.
Hence, option D is correct.
