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Dima020 [189]
2 years ago
10

What is the answer please help

Mathematics
1 answer:
Verizon [17]2 years ago
3 0

Answer:

is the number 4

so 13/16 3/16

Step-by-step explanation:

You might be interested in
What is 0.5 repeating as a fraction in simplest form
Solnce55 [7]

Answer:

5/9

Step-by-step explanation:

Start be letting x = 0.555...

Our original equation is:

x = 0.555...

There is only one digit repeating, the 5, so we multiply both sides of that equation by 10 and write it above the original equation.

10x = 5.555...

   x = 0.555...

Now we subtract the second equation from the first equation as written above.

9x = 5

Divide both sides by 9.

x = 5/9

0.555... = 5/9

6 0
3 years ago
Find a counterexample to disprove the statement "The Associative Property is true for division."
MaRussiya [10]
The associative property makes it so whichever which way the numbers are the answer will be the same but as shown in the picture this isn't true for this statement because the answers become completely different depending on where the numbers are in the equation.
6 divided by 3 is NOT equal to 3 divided by 6 which disproves that property.

5 0
3 years ago
13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult
Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that \frac{ab}{m} is and integer.

As m= vb, then \frac{m}{b} is an integer, lets say \frac{m}{b}=v; and as m=ua, then \frac{m}{a}=u.

So \frac{ab}{m}v=\frac{ab}{m}\frac{m}{b}=a, so \frac{ab}{m} divides a; on the other hand, \frac{ab}{m}u=\frac{ab}{m}\frac{m}{a}=b, so \frac{ab}{m} divides b. From this we can conclude that \frac{ab}{m} is a common divisor of a and b.

4 0
3 years ago
Help a sis out ??
REY [17]

Answer:

B

Step-by-step explanation:

let base be b then height h = 2b + 4

The area (A) of a triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the height ) , then

A = \frac{1}{2} b(2b + 4) ← distribute parenthesis

A = b² + 2b

When b = 16 , then

A = 16² + 2(16) = 256 + 32 = 288 in²

7 0
2 years ago
There are 5.280 feet in a mile. What is the total number of feet in 6 milies?
qwelly [4]
1mile=5.280
6miles=6*5.280
= 31.680

So option B is the answer...


If this helps you plzz Mark me as brainlest...
7 0
3 years ago
Read 2 more answers
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