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d1i1m1o1n [39]
3 years ago
6

Rationalize the denominator​

Mathematics
2 answers:
Mamont248 [21]3 years ago
7 0

Answer:

\huge\color{purple}\boxed{\colorbox{black}{Answer♡}}

\frac{2}{ \sqrt{7}  - 1}  \\  =  >  \frac{2}{ \sqrt{7}  - 1}  \times  \frac{ \sqrt{7}  + 1}{ \sqrt{7}  + 1}  \\  =  >  \frac{2( \sqrt{7}  + 1)}{ \sqrt{7} {}^{2}   - 1 {}^{2} } \\  =  >  \frac{2 \sqrt{7}  + 2}{7 - 1} \\  =  >  \frac{2( \sqrt{7}  + 1)}{6}  \\  =  >  \frac{ \sqrt{7}  + 1}{3}

<h2>———————————————</h2>

\color{red}\boxed{\colorbox{skyblue}{Additional Information~}}

<h3>Here..</h3>
  • Step 3 contains the algebraic identity

( a + b ) × ( a - b ) = a² - b²

  • Also.. in the very last step ,

we earlier had 2 multiplied to rest of the numerator and 6 in the denominator..

we simply divided both the numerator as well as denominator by 2 and hence got the result obtained.

‎ ‎

‎ ‎

‎ ‎

hope helpful~

<h3>~Be Brainly!</h3><h3>~Exhausted Zombie</h3>
zepelin [54]3 years ago
3 0
Here’s the answer….hope it helps ;)

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Evaluate the function f\left(x\right)=5x+2\mid11-5x\mid-4f(x)=5x+2∣11−5x∣−4 for x = -5.
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Answer:

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Step-by-step explanation:

Given

f\left(x\right)=5x+2\mid11-5x\mid-4

Required

Solve for x = -5

This implies that we substitute -5 for x in f\left(x\right)=5x+2\mid11-5x\mid-4

f\left(5\right)=5(-5)+2\mid11-5(-5)\mid-4

Open all brackets

f\left(5\right) = -25+2\mid11+25\mid-4

f\left(5\right) = -25+2\mid36\mid-4

Absolute value of 36 is 36; Wo, we have:

f\left(5\right) = -25+2*36-4

f\left(5\right) = -25+72-4

f\left(5\right) = 43

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