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Fudgin [204]
3 years ago
9

My Christmas present to you​

Mathematics
1 answer:
Yuki888 [10]3 years ago
8 0

Answer:

Step-by-step explanation:

thx

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Please help my guys plaese
bixtya [17]

Answer: I think it’s A

Step-by-step explanation:

Not sure though

7 0
3 years ago
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In how many ways can a president and a vice president be randomly selected from a class of 20 students?
SpyIntel [72]

Answer:

n how many ways can a president, vice president, and a secretary be chosen? It is 12X11X10. Permutation of n things taken r at a time: nPr=n!/(n-r)! 12P3=12*11*10*9!/9!= 12*11*10=1320 ways.

Step-by-step explanation:

7 0
4 years ago
X-2/x+4 = x-3/x+1 Find 5he answer​
Nady [450]

Answer:

Find the LCD of the terms in the equation. x

Multiply each term by x and simplify.

x²−2+4x=x²−3+x

Solve the equation.

x=−1/3

Step-by-step explanation:

3 0
3 years ago
The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is
Firlakuza [10]
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.

An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.



Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.

Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.


Part C:
Given that </span><span>Natalie can only attend a school in her designated zone and that Natalie's zone is defined by y < −2x + 2.

To identify the schools that Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.

For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true

For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true

For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false

For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true

For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false

For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
7 0
4 years ago
Find the solution set. x^2+5x-6=0
vladimir2022 [97]
\displaystyle x^2+5x-6=0 \\ \\ \Delta=b^2-4ac\\ \Delta=5^2-4\cdot1\cdot(-6) \\ \Delta=25+24=49 \\ \\ X_{1,2}= \frac{-b \pm \sqrt{\Delta} }{2a} \\ \\ X_1= \frac{-5-7}{2} =  -\frac{12}{2} =-6 \\ \\ X_2= \frac{-5+7}{2}= \frac{2}{2} =1 \\ \\ \text{The solution set: -6 and 1}
6 0
3 years ago
Read 2 more answers
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