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Vesnalui [34]
2 years ago
14

I'll give brainliest

Chemistry
2 answers:
ss7ja [257]2 years ago
8 0

Answer:

b,d,f

Explanation:your welcome give brainilest

Pavlova-9 [17]2 years ago
6 0

Answer:

b,d,f

Explanation:

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A solution is made by mixing 34.5 g of sugar with 75.0 g of water. What is the mass percent of sugar in this solution?
lubasha [3.4K]

the mass percent of sugar in this solution is 46%.

Answer:

Solution given:

mass of solute=34.5g

mass of solvent=75g

mass percent=\frac{mass\:of\:solute}{mass\:of \:solvent}*100\%

=\bold{\frac{34.5}{75.0}*100\%=46\%}

5 0
3 years ago
HELP................!!!!
expeople1 [14]
Your answer is 1-3-2-4 , grass sand water rock
3 0
3 years ago
If Matteo has a model car with a volume of 100 mL and a mass of 200 g, what is the density of their model car?
OLEGan [10]

Answer:

<h2>2 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{200}{100}  \\

We have the final answer as

<h3>2 g/mL</h3>

Hope this helps you

6 0
3 years ago
Describe the mass of the reactants and products given the balanced chemical reaction.
Andru [333]

Answer:

The mass of the reactants equals the mass of the products.

5 0
3 years ago
A 0.500 m solution of a weak base has a ph of 9.75. what is the base hydrolysis constant, kb, for the weak base?
Vladimir [108]
When we have PH = 9.75
So we can get POH = 14 - 9.75 = 4.25 
and when POH = - ㏒[OH-]
by substitution:
4.25 = -㏒[OH-]
∴[OH] = 5.6x10^-5
from this reaction equation:
BOH ↔ B+  + OH-
∴[OH-] = [B+]= 5.6x10^-5 M
and Equ [BOH] = 0.5 m - X
                          = 0.5 - (5.6x10^-5)
                          =  0.4999
∴ Kb = [OH-][B+]/[BOH]
         = (5.6x10^-5)^2 / 0.4999
         = 6.27x10^-9

8 0
2 years ago
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