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Aloiza [94]
3 years ago
5

How do you design video games

Computers and Technology
1 answer:
KiRa [710]3 years ago
7 0
Code video games or visuals
You might be interested in
Which type of footwear should be worn while working on a hybrid vehicle?
Dmitrij [34]

Hello there!

Shoes with rubber souls would be the best bet.

7 0
3 years ago
Read 2 more answers
Given public class Fishing { byte b1 = 4; int i1 = 123456; long L1 = (long) i1; //Line A short s2 = (short) i1; //Line B byte b2
Aleksandr [31]

Answer:

Line E.

Explanation:

The  given program is as follows:

public class Fishing {

   byte b1 = 4; int i1 = 123456; long L1 = (long) i1;   //Line A

   short s2 = (short) i1;     //Line B

   byte b2 = (byte) i1;     //Line C

   int i2 = (int)123.456;    //Line D

   byte b3 = b1 + 7;     //Line E

   }

In the above code Line E will not compile and give following compilation error:

error: incompatible types: possible lossy conversion from int to byte

This error is coming because in Java b1 + 7 will be interpreted as int variable expression. Therefore in order to make code of Line E work the expression should be type casted as byte.  

The correct code will be as follows:

public class Fishing {

   byte b1 = 4; int i1 = 123456; long L1 = (long) i1;   //Line A

   short s2 = (short) i1;     //Line B

   byte b2 = (byte) i1;     //Line C

   int i2 = (int)123.456;    //Line D

   byte b3 = (byte)(b1 + 7);     //Line E

   }

5 0
3 years ago
2. Using the Book class developed in HW 4, write an application, BookLibrary, that creates a library (array) of up to 10 books a
qwelly [4]

BookLibrary, that creates a library (array) of up to 10 books. If the user selects the add option, issue an error message if the library is full.If the book with that title exists, issue an error message

Explanation:

import java.util.Scanner;

import java.util.Arrays;

public class Derro_BooksLibrary {

public static void main(String[] args) {

 Derro_Books[] Library = new Derro_Books[10];

 Scanner scan = new Scanner(System.in);

 Derro_Books book1 = new Derro_Books("", 20);

 Derro_Books book2 = new Derro_Books("hi", 10);

 Library[0] = book1;

 Library[1] = book2;

 System.out.println("Enter 1 for add, 2 for delete, 3 for change, 4 to stop application: ");

 int answer = scan.nextInt();

 int counter = 0;

 int z = 0;

 while (true) {

  if (answer == 1) {

   for (Derro_Books book : Library) {

    counter = counter + 1;

   }

   if (counter == 10) {

    System.out.println("Library full");

   }

   System.out.println("Enter Title: ");

   String title = scan.nextLine();

   for (int i = 0; i < Library.length; i++) {

    if (title == Library[i].getTitle()) {

     System.out.println("No Duplicated Books Titles Are Allowed");

     break;

    }

    else {

     z++;

    }

   }

   if (z < Library.length) {

   System.out.println("Enter number of pages: ");

   int pages = scan.nextInt();

   Library[z + 1] = new Derro_Books(title, pages);

  }

  if (answer == 2){

   if (Library.length == 0) {

    System.out.println("Library is empty");

   }

   System.out.println("Enter title of book: ");

   String title2 = scan.nextLine();

   for (int d = 0; d < Library.length; d++) {

    if (title2 == Library[d].getTitle())

     // Delete book

     System.out.println("Deleted book: " + title2);

    else

     System.out.println("Book does not exist");

   }

  }

  if (answer == 3) {

   if (Library.length == 0) {

    System.out.println("Library is empty.");

   } else {

    System.out.println("Enter book title: ");

    String title3 = scan.nextLine();

    for (int y = 0; y < Library.length; y++) {

     if (title3 != Library[y].getTitle())

      continue;

     else {

      System.out.println("Enter number of pages: ");

      int pages = scan.nextInt();

      Library[y] = new Derro_Books(title3, pages);

     }

    }

   }

  }

  String[] StringList = new String[10];

  for (int y = 0; y < Library.length; y++) {

   StringList[y] = Library[y].getTitle();

  }

  Arrays.sort(StringList);

  for (String bookt : StringList) {

   System.out.println(bookt + Library);

  }

 }

}

}

}

6 0
3 years ago
Write a function called getChar that has no function inputs, but takes in two character inputs from the user (in1 and in2) and o
bearhunter [10]

Answer:

def getChar():

   while True:

       in1 = input('Enter first char: ')

       try:

           if len(in1) != 1:

               raise

           else:

               in2 = input('Enter second char: ')

               if len(in2) != 1:

                   raise

               else:

                   break

       except:

           print('Enter just one character')

   return in1, in2

def chars2string(in1,in2):

   print(in1*5 + in2*5)

def main():

   ls = getChar()

   in1 = ls[0]

   in2 = ls[1]

   chars2string(in1, in2)

if __name__ == '__main__':

   main()

Explanation:

The programming language used is python 3.

The script first defines a function getChar and makes use of a while loop in combination with try and except blocks and IF statements, the code ensures that both inputs that are entered by the user after the prompt are 1 in length. i.e. Just one character. This function returns the two characters that were entered.

The second function that is defined is chars2string this function takes two arguments, It repeats each argument five times and returns a joined string.

Finally, the main function is defined and it calls the getChar function  first, the values that are returned by this function is assigned to two variables, that is then passed on to the chars2string function. The main function is called and the Joined string is printed to the screen.

3 0
3 years ago
Design and implement a program to display each directory entry information (files and directories) of current directory, and wit
FromTheMoon [43]

Answer: The code below can display directory as stated in the question

Explanation:

char *

gnu_getcwd ()

{

 size_t size = 100;

 while (1)

   {

     char *buffer = (char *) xmalloc (size);

     if (getcwd (buffer, size) == buffer)

return buffer;

     free (buffer);

     if (errno != ERANGE)

       return 0;

     size *= 2;

   }

}

3 0
3 years ago
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