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Alchen [17]
2 years ago
11

PLEASE HELP WILL MARK BRAINLIEST THANK YOU SO MUCH

Mathematics
2 answers:
Marina CMI [18]2 years ago
6 0

Answer:

3

Step-by-step explanation:

brainliest to other person

Jet001 [13]2 years ago
4 0

Answer:

It should be 3

Step-by-step explanation:

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Adidea Corp. estimates that $5,670 of its accounts receivables are uncollectible. How will the company record the transaction?
sergiy2304 [10]

Answer:

The transaction will be recorded by the company as :

DR : Non-collectibles $5670  

CR : Accounts receivable $5670

Step-by-step explanation:

Amount of money estimated = $5670

The amount which is non-collectible is recorded as a DEBIT transaction by the company because the amount in the non-collectible account can't be received by the company.

But, the amount in the receivables is the amount which is available for receiving and can be received by the company. So, receivable transaction is marked as CREDIT by the company.

Thus, the transaction will be recorded by the company as :

DR : Non-collectibles $5670  

CR : Accounts receivable $5670

4 0
3 years ago
What is the completely factored form of f(x)=x3+5x2+4x−6?
Gre4nikov [31]
f(x)=x^3+5x^2+4x-6
f(-3)=(-3)^3+5(-3)^2+4(-3)-6=0\implies x+3\text{ is a factor of }f(x)

Synthetic division yields

-3  |  1   5   4   -6
.    |      -3  -6    6
- - - - - - - - - - - - -
.    |  1   2  -2    0

which translates to

\dfrac{x^3+5x^2+4x-6}{x+3}=x^2+2x-2

with remainder 0. Now by the quadratic formula,

x^2+2x-2=0\implies x=\dfrac{-2\pm\sqrt{2^2-4(1)(-2)}}2=-1\pm\sqrt3

and so

f(x)=x^3+5x^2+4x-6=(x+3)(x-(-1+\sqrt3))(x-(-1-\sqrt3))
3 0
3 years ago
Form a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3
polet [3.4K]

The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is x^3-3x^2-x+3=0

Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

If -1, 1 and 3 are real zeros, it can be written as:

x= -1, x= 1, and x = 3

or x+1=0, x-1=0 and x-3=0

Finding polynomial by multiply these factors:

(x+1)(x-1)(x-3)=0\\(x+1)(x(x-3)-1(x-3))=0\\(x+1)(x^2-3x-x+3)=0\\(x+1)(x^2-4x+3)=0\\x(x^2-4x+3)+1(x^2-4x+3)=0\\x^3-4x^2+3x+x^2-4x+3=0\\Combining\,\,like\,\,terms:\\x^3-4x^2+x^2+3x-4x+3=0\\x^3-3x^2-x+3=0

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is x^3-3x^2-x+3=0

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

  • brainly.com/question/1464739
  • brainly.com/question/2568692
  • brainly.com/question/10771256

#learnwithBrainly

8 0
4 years ago
Why are there certain question where you multiply to a power and some you don't. Like tree diagrams. This is for probability of
rewona [7]

Answer:

ok.

Step-by-step explanation:

3 0
3 years ago
Collin wants to solve this system of equations. Which number can he multiply the first equation by so that when the two equation
siniylev [52]
If u multiply the first equation by -4, u get -2x - y = -20

and when u add the 2 equations..
-2x - y = -20
2x + 3/8y = 5
-----------------
0 - 5/8y = -15.....u notice that the x terms r eliminated.

4 0
3 years ago
Read 2 more answers
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