The code of five digits is of the form:
A B C D F
Where A (the first digit) may be any of 9 digits (because 0 is excluded)
B, C, and D, may be each any of 10 digits (0 - 9)
F (the last digit) may be 0, 2, 4, 6 or 8, i.e. 5 different digits.
So the number of different available codes is:
9 * 10 * 10 * 10 * 5 = 45,000.
Answer: 45,000
Answer:
✔️saves time spent manually creating multiple tasks
Explanation:
I did it on edge
Answer:
#include <iostream>
using namespace std;
int main()
{
string str;
cout<<"Enter the string: ";
cin>>str;
for(int i=0;str[i]!='\0';i++){
if(str[i]=='e'){
str[i]='x';
}
}
cout<<"the string is: "<<str<<endl;
return 0;
}
Explanation:
First, include the library iostream for using the input/output instructions.
Create the main function and declare the variables.
Then, use the cout instruction and print the message on the screen.
cin store the string enter by the user into a variable.
After that, take a for loop and if-else statement for checking the condition if the string contains the 'e', then change that alphabet to 'x'.
This process continues until the string not empty.
Finally, print the updated string.
Depends on what kind of goal.
If I gave a goal of eating 8 hot dogs then a barrier would be a physical will of your body to not eat more. It would be a limit your body can take so it’s different from a mental or other barrier.
If you wanted to cross an area of land but there is a fence in the way then that’s another type of barrier.
Or there are mental barriers. If you wanted to ask someone out to prom, you may be stopped by a mental barrier of self hatred. Feeling like you’re not good enough.
Hopefully this helps!
