Answer:
0.209M
Explanation:
M1V1=M2V2
(28.5 mL)(0.183M)=(25.0mL)(M)
M2= 0.209M
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Answer: The final temperature (T) will be;
16.23°c
Explanation: To find the final temperature of any mixture of substance with an initial temperature use the formula;
M1c(T-T1) + M2c(T-T2)=0
c is the specific heat capacity of the two different substance, but because ice and water are the same, we assume c to be 1
T= final temperature of the mixture
T1= initial temperature of the ice= -10.2°c
T2= initial temperature of the water= 19.7°c
M1= mass of ice= 33.1g
M2= mass of water= 251g
Using the formula above
33.1(T-(-10.2)) + 251(T-19.7)=0
Solving out the bracket
33.1T + 337.62 + 251T - 4944.7 = 0
Collecting like terms to both side of the equation and solving
33.1T + 251T = 4944.7 - 33.62
284.1T = 4607.08
T = 4607.08÷284.1 = 16.23°c
Mechanical Energy and Thermal Energy
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