Answer:
18-3-12
15-12
3 is the answer
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Step-by-step explanation:
Basically anything greater than zero...k>0
Substitute the value of y in the equation as -1,
(-1)^2-31(-1)-17 = 1+31-17 = 15
Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
V = l * w * h
470.40 = 6.4 * 9.8 * h
Multiply the length and width on the right side of the equation.
470.40 = 62.72 * h
Divide both sides by 62.72
7.5 cm = h
CHECK
V = l * w * h
V = 6.4 * 9.8 * 7.5
V = 470.4 cm^3
