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2 years ago

Solve the quadratic equation given. 6x2 - 24 = 0

1 answer:

6 0

${6x}^{2} - 24 = 0 \\ = > 6( {x}^{2} - 4) = 0 \\ = > 6 {((x)}^{2} - {(2)}^{2} ) = 0 \\ = > 6(x - 2)(x + 2) = 0 \\ = > 6(x - 2) = 0 \: \: \: or \: \: 6(x + 2) = 0 \\ = > 6x - 12 = 0 \: \: \: or \: \: \: 6x + 12 = 0 \\ = > x = 2 \: \: \: or \: \: \: x = - 2$

Hope you could get an idea from here.

Doubt clarification - use comment section.

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3 years ago

The sum of 4 consecutive even integers is -12. find the largest integer.

Ipatiy [6.2K]

Answer:

The largest even integer is 0

Step-by-step explanation:

Given as :

The sum of four consecutive even number = - 12

Let The first even number = 2 x

The second even number = (2 x + 2)

The third even number = (2 x + 4)

The fourth even number = (2 x + 6)

<u>According to question</u>

sum of four consecutive even number = - 12

Or, 2 x + (2 x + 2) + (2 x + 4) + (2 x + 6) = - 12

Or, (2 x + 2 x + 2 x + 2 x) + (2 + 4 + 6) = - 12

Or, 8 x + 12 = - 12

Or, 8 x = - 12 - 12

Or, 8 x = - 24

∴ x = $\frac{- 24}{8}$

i.e x = - 3

now, putting the value of x

The first even number = 2 × - 3 = - 6

The second even number = (2 × - 3 + 2) = - 6 + 2 = - 4

The third even number = (2 × - 3 + 4) = - 6 + 4 = - 2

The fourth even number = (2 × - 3 + 6) = - 6 + 6 = 0

So, The largest even integer = 0

Hence, The largest even integer is 0 Answer

6 0

3 years ago