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2 years ago

10

Construct one circle with center A passing through point B and another circle with center A passing through C. Circles with comm

on centers are called concentric circles. We’ll refer to the circle that passes through B as AB and the one that passes through C as AC. Besides being concentric, what is the relationship between circles AB and AC? someone please help me

1 answer:

solniwko [45]2 years ago

3 0

Answer:

The two circles centered at point A are concentric and similar.

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The data to the right represent the weights (in grams) of a random sample of 50 candies. Complete parts (a) through (f). 0.92

Inessa05 [86]

Answer:

0.069

Step-by-step explanation:

The given data set is

0.92, 0.87, 0.88, 0.82, 0.82, 0.87, 0.97, 0.86, 0.89, 0.84, 0.81, 0.88, 0.77, 0.86, 0.93, 0.84, 0.72, 0.82, 0.74, 0.83, 0.93, 0.75, 0.79, 0.91, 0.84, 0.91, 0.88, 0.88, 0.83, 0.78, 0.99, 0.81, 0.78, 0.75, 0.82, 0.76, 0.82, 0.87, 0.91, 0.77, 0.72, 0.94, 0.71, 0.73, 0.81, 0.81, 0.86, 0.93, 0.93, 0.82.

Formula for mean:

$Mean=\frac{\sum x}{n}$

Sum of all terms = 41.98

Mean of the data set is

$Mean=\frac{41.98}{50}$

$Mean=0.8396$

Formula for standard deviation for population:

$\sigma=\sqrt{\frac{\sum (x-\overline{x})^2}{n}}$

Formula for standard deviation for sample:

$\sigma=\sqrt{\frac{\sum (x-\overline{x})^2}{n-1}}$

$\sigma=\sqrt{\frac{0.231792}{50-1}}$

$\sigma=\sqrt{0.004730449}$

$\sigma=0.06877826$

$\sigma\approx 0.069$

Therefore, the standard deviation of the data set is 0.069.

5 0

3 years ago

Solve. −3 2/3x=−2 1/5 What is the solution to the equation? Enter your answer as a simplified fraction in the box. x =

Artyom0805 [142]

Answer:

i think it is: x=3/5

Step-by-step explanation:

hope it helps

8 0

2 years ago

The mean number of words per minute (wpm) read by sixth graders is 89 with a variance of 625. if 96 sixth graders are randomly s

Luba_88 [7]

The z-score of the information given is:
z=(x-μ)/σ
where
μ-mean
σ- standard deviation

from the information given:
x=93.02
μ=89
σ=√625=25
hence
z=(93.02-89)/25
z=0.1608
thus
P(X≥x)=1-0.5636=0.4364=43.64%

6 0

2 years ago

What is the value of x?<br><br> 27(x+4)=−6<br><br><br> −35<br><br> −25<br><br> 25<br><br> 35

Oksanka [162]

x = -38/9 !!!

27(x+4)=−6

Step 1: Simplify both sides of the equation.

27(x+4)=−6

(27)(x)+(27)(4)=−6 (Distribute)

27x+108=−6

Step 2: Subtract 108 from both sides.

27x+108−108=−6−108

27x=−114

Step 3: Divide both sides by 27.

27x/27=−114/27

x=−389

6 0

3 years ago

What is the nth term?

kumpel [21]

Let $a_k$ denote the <em>k</em>th term of the sequence. Then

$a_k=a_1+d(k-1)$

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.

The sum of the first <em>n</em> terms is

$S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n$

From the formula for $a_k$ , we get

$S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)$

$S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k$

$S_n=na_1+\dfrac{d(n-1)n}2$

$S_n=\dfrac n2(2a_1-d+dn)$

So we have $d=-5$ , and $2a_1-d=16$ so that $a_1=\frac{11}2$ .

Then the <em>n</em>th term in the sequence is

$a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}$

7 0

3 years ago