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3 years ago

There are 30 stuffed animals in a gift gallery.

Mathematics

2 answers:

Komok [63]3 years ago

6 0

Answer:

= 37

Step-by-step explanation:

30+7= 37

olganol [36]3 years ago

5 0

30+7 equals 37. There are 37 stuffed animals.

You might be interested in

Is x=3 a zero of f(x)=4x^4-x^3-52x^2-35x+12

lora16 [44]

Answer:

Step-by-step explanation:

If x = 3 is a zero, then f(3) = 0

f(3)

= 4 $(3)^{4}$ - 3³ - 52(3)² - 35(3) + 12

= 324 - 27 - 468 - 105 + 12

= - 264

Since f(3) ≠ 0 then x = 3 is not a zero of f(x)

5 0

3 years ago

Researchers are interested in determining whether more men than women prefer Coca Cola to Pepsi. In a random sample of 300 men,

kobusy [5.1K]

Answer: 0.17 ± 0.096

Step-by-step explanation:

Confidence interval for difference between the population proportion :

$p_1-p_2\pm z^*\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}$

, where $p_1$ = sample proportion for population 1.

$p_2$ = sample proportion for population 2.

$n_1$ = Sample size from population 1.

$n_2$ = Sample size from population 1.

As per given , we have

Population

$p_1=0.65\ \ \& \ \ p_2=0.48$

$n_1=300\ \ \ \&\ \ n_2=400$

Critical z-value for 99% confidence level is z*=2.576 [By z-table]

Now , the 99% confidence interval estimate for the difference between the percentages of men and women who prefer Coca Cola over Pepsi :

$(0.65-0.48)\pm (2.576)\sqrt{\dfrac{(0.65)(1-0.65)}{300}+\dfrac{(0.48)(1-0.48)}{400}}\\\\= 0.17\pm(2.576)\sqrt{0.0007583+0.000624}\\\\=0.17\pm(2.576)\sqrt{0.0013823}\\\\=0.17\pm(2.576)(0.03718)\\\\=0.17\pm0.09577568\\\\\approx0.17\pm0.096$ \

Hence, the correct answer is 0.17 ± 0.096.

6 0

3 years ago

Read 2 more answers

Find the amount in a account where $200 is invested at 3.5% compounded quarterly for a period of 3 years.

AlexFokin [52]

The amount after 3 years would be $221.74

<u>Explanation:</u>

Given:

Principal, P = $200

Rate of interest, r = 3.5%

Time, t = 3 years

Amount, A = ?

We know:

$A = P(1+\frac{r}{100})^t$

Substituting the value we get:

$A = 200(1+\frac{3.5}{100} )^3\\\\A = 200 X 1.108\\\\A = 221.74$

Therefore, the amount after 3 years would be $221.74

3 0

3 years ago

A rectangular pool is to be built on a lot that measures 20 m by 12 m. A wooden deck of uniform width, equal to the area of the

frutty [35]

The length and breadth(width) of the pool are

$l\approx15.7m\text{ and }b\approx7.7m$

Let

$l=\text{length of the side of the pool}\\b=\text{breadth of the pool side}\\w=\text{the width of the strip of deck surrounding the pool}$

From the question, we can build the following relationships

$l+2w=20\\b+2w=12$

subtracting to eliminate $w$ (we do not even need it!)

$l-b=8\\b=l-8$

we can also build another relationship from the question. Since the area of the strip equals the area of the pool:

$lb+lb=2lb=20\times 12\\lb=120$

We have two unknowns, $l$ and $b$ . Eliminate $b$

$lb=120\\l(l-8)=120\\l^2-8l-120=0$

If we solve the quadratic equation for $l$ , we get

$l=4+2\sqrt{34}\approx 15.7m$

and

$b=l-8\\b=(4+2\sqrt{34})-8\\b=2\sqrt{34}-4\approx7.7m$

The length and breadth(width) of the pool are

$l\approx15.7m\text{ and }b\approx7.7m$

Learn more about area here: brainly.com/question/1447350

7 0

2 years ago

QF Q5.) Estimate the age of the paintings.

nikdorinn [45]

A=A₀ $e^{0.000121t}$
A/A₀=24%=0.24
0.24= $e^{0.000121t}$
0.000121t=ln(0.24)
t=ln(0.24)/0.000121
=-11794.35
so painting is 11794 years old

8 0

4 years ago