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Goshia [24]
3 years ago
15

There are 30 stuffed animals in a gift gallery.

Mathematics
2 answers:
Komok [63]3 years ago
6 0

Answer:

= 37

Step-by-step explanation:

30+7= 37

olganol [36]3 years ago
5 0

30+7 equals 37. There are 37 stuffed animals.

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Is x=3 a zero of f(x)=4x^4-x^3-52x^2-35x+12
lora16 [44]

Answer:

no

Step-by-step explanation:

If x = 3 is a zero, then f(3) = 0

f(3)

= 4(3)^{4} - 3³ - 52(3)² - 35(3) + 12

= 324 - 27 - 468 - 105 + 12

= - 264

Since f(3) ≠ 0 then x = 3 is not a zero of f(x)

5 0
3 years ago
Researchers are interested in determining whether more men than women prefer Coca Cola to Pepsi. In a random sample of 300 men,
kobusy [5.1K]

Answer: 0.17 ± 0.096

Step-by-step explanation:

Confidence interval for difference between the population proportion :

p_1-p_2\pm z^*\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}

, where p_1 = sample proportion for population 1.

 p_2 = sample proportion for population 2.

n_1 = Sample size from population 1.

n_2 = Sample size from population 1.

As per given , we have

Population

p_1=0.65\ \ \& \ \ p_2=0.48

n_1=300\ \ \ \&\ \ n_2=400

Critical z-value for 99% confidence level is z*=2.576  [By z-table]

Now , the 99% confidence interval estimate for the difference between the percentages of men and women who prefer Coca Cola over Pepsi :

(0.65-0.48)\pm (2.576)\sqrt{\dfrac{(0.65)(1-0.65)}{300}+\dfrac{(0.48)(1-0.48)}{400}}\\\\= 0.17\pm(2.576)\sqrt{0.0007583+0.000624}\\\\=0.17\pm(2.576)\sqrt{0.0013823}\\\\=0.17\pm(2.576)(0.03718)\\\\=0.17\pm0.09577568\\\\\approx0.17\pm0.096\

Hence, the correct answer is 0.17 ± 0.096.

6 0
3 years ago
Read 2 more answers
Find the amount in a account where $200 is invested at 3.5% compounded quarterly for a period of 3 years.
AlexFokin [52]

The amount after 3 years would be $221.74

<u>Explanation:</u>

Given:

Principal, P = $200

Rate of interest, r = 3.5%

Time, t = 3 years

Amount, A = ?

We know:

A = P(1+\frac{r}{100})^t

Substituting the value we get:

A = 200(1+\frac{3.5}{100} )^3\\\\A = 200 X 1.108\\\\A = 221.74

Therefore, the amount after 3 years would be $221.74

3 0
3 years ago
A rectangular pool is to be built on a lot that measures 20 m by 12 m. A wooden deck of uniform width, equal to the area of the
frutty [35]

The length and breadth(width) of the pool are

l\approx15.7m\text{ and }b\approx7.7m

Let

l=\text{length of the side of the pool}\\b=\text{breadth of the pool side}\\w=\text{the width of the strip of deck surrounding the pool}

From the question, we can build the following relationships

l+2w=20\\b+2w=12

subtracting to eliminate w (we do not even need it!)

l-b=8\\b=l-8

we can also build another relationship from the question. Since the area of the strip equals the area of the pool:

lb+lb=2lb=20\times 12\\lb=120

We have two unknowns, l and b. Eliminate b

lb=120\\l(l-8)=120\\l^2-8l-120=0

If we solve the quadratic equation for l, we get

l=4+2\sqrt{34}\approx 15.7m

and

b=l-8\\b=(4+2\sqrt{34})-8\\b=2\sqrt{34}-4\approx7.7m

The length and breadth(width) of the pool are

l\approx15.7m\text{ and }b\approx7.7m

Learn more about area here: brainly.com/question/1447350

7 0
2 years ago
QF Q5.) Estimate the age of the paintings.
nikdorinn [45]
A=A₀e^{0.000121t}
A/A₀=24%=0.24
0.24=e^{0.000121t}
0.000121t=ln(0.24)
t=ln(0.24)/0.000121
=-11794.35
so painting is 11794 years old
8 0
4 years ago
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