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DENIUS [597]
3 years ago
6

What is the area of a parallelogram with a length of 9in and a height of 10in and a width of 8in

Mathematics
2 answers:
olganol [36]3 years ago
3 0

Answer:

72 sq in.

Step-by-step explanation:

I'm not sure what you mean, but it sounds like the base is 9 in, the side is 10 in, and the height is 8 in. If so, the area is 9 * 8 = 72 sq in.

Svetlanka [38]3 years ago
3 0

Answer:

i think the person above is correct

Step-by-step explanation:

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Mama L [17]

Answer:

d=hf+5

Step-by-step explanation:

Step 1: Factor out variable d.

d(f+5)=h

Step 2: Divide both sides by f+5.

d(f+5)f+5=hf+5

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8 0
3 years ago
What is the area of the poster board that she has left
steposvetlana [31]
Find the area of the parallelogram, find the area of the triangle, then subtract the triangle's area from the area of the parallelogram.

Area of Parallelogram:
A= base * height
A= 20 in * 10 in
A= 200 in^2

Area of Triangle:
A= 1/2 base * height
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A= 1/2 (90)
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Area of Poster Left:
subtract the difference
A= Parallelogram Area - Triangle Area
A= 200 in^2 - 45 in^2
A= 155 in^2

ANSWER: 155 in^2 is the area of the poster board she has left.

Hope this helps! :)
5 0
3 years ago
The sum of two whole numbers is 84, and their positive difference is 18.What are the two numbers? Please help
Vlad1618 [11]

Answer:

Step-by-step explanation:

8 0
3 years ago
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Answer:

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Answer: 9/16

Work Shown:

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