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3 years ago

12

The valley school printed 385 tickets for the school play in spring 3/5 of the tickets were sold out by January how many tickets

remain to be sold

1 answer:

morpeh [17]3 years ago

3 0

154 tickets remain to be sold

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Calculate (A⃗ ×B⃗ )⋅C⃗ for the three vectors A⃗ with magnitude A = 5.08 and angle θA = 25.6 ∘ measured in the sense from the +x

alexgriva [62]

Answer:

(A⃗ ×B⃗ )⋅C⃗ = - 76.415

Step-by-step explanation:

First we need to calculate (A⃗ ×B⃗ ) :

(A⃗ ×B⃗ ) = A.B.sin (α).n

Where A is the magnitude of A⃗

Where B is the magnitude of B⃗

Where α is the angle between A⃗ and B⃗ = 63.9 - 25.6 = 38.3

Finally n is the vector orthogonal to A⃗ and B⃗

n magnitude is 1 and his direction is given by the right hand-rule

so n = ( 0 , 0 , 1 )

(A⃗ ×B⃗ ) = A.B.sin (α).n = 5.08 . 3.94 . sin (38.3) . (0 , 0 , 1 ) = (0,0,12.4)

C⃗ can be written as C.(0,0,-1) because of his +z - direction

C.(0,0,-1) = 6.16.(0,0,-1) = (0,0,-6.16)

(A⃗ ×B⃗ )⋅C⃗ = (0,0,12.4).(0,0,-6.16) = -76.41480787 = -76.415

8 0

3 years ago

What is the Inequality and Solution of: The sum of a number and 19 is at least 8.2 ?

Misha Larkins [42]

X + 19 >= 8.2

x >= 8.2 -19 >= -10.8

3 0

4 years ago

What is equivalent to 9^x=27

erma4kov [3.2K]

If you meant to solve for x...

$9^x=27 \\
(3^2)^x=3^3\\
3^{2x}=3^3\\
2x=3\\
x=\dfrac{3}{2}$

8 0

3 years ago

How do you do this?<br> Because i don't know how to do it :>

Sindrei [870]

Answer:

£ 7.95

Step-by-step explanation:

Let the total money = £ x

Money spend on drinks and cake = 1.45 + 1.20 = £ 2.65

Money left with her = (2/3) of x

So, money spend = (1/3) of x

$\dfrac{1}{3}*x= 2.65\\\\\\x=2.65*3\\\\$

x = £ 7.95

7 0

3 years ago

Find the indicated sum of each sequence S8 of -2,-13,-24,-35

valentina_108 [34]

Answer:

The sum of the arithmetic sequence is $S_{8}=-324$ .

Step-by-step explanation:

A sequence is a set of numbers that are in order.

In an arithmetic sequence the difference between one term and the next is a constant. In other words, we just add the same value each time infinitely.

If the first term of an arithmetic sequence is $a_1$ and the common difference is d, then the nth term of the sequence is given by:

$a_{n}=a_{1}+(n-1)d$

For the sequence

$-2,-13,-24,-35,...$

The pattern is continued by adding -11 to the last number each time.

An arithmetic series is the sum of an arithmetic sequence. We find the sum by adding the first, $a_1$ and last term, $a_n$ , divide by 2 in order to get the mean of the two values and then multiply by the number of values, <em>n</em>

<em> </em> $S_{n}=\frac{n}{2}(a_{1}+a_{n})$ <em />

The sum of the arithmetic sequence is

$a_{8}=-2+(8-1)(-11)=-2-77=-79$

$S_{8}=\frac{8}{2}(-2-79})=4\left(-2-79\right)=4\left(-81\right)=-324$

3 0

4 years ago