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m_a_m_a [10]
3 years ago
11

Which requires more energy to move an electron?

Chemistry
2 answers:
Mandarinka [93]3 years ago
4 0

Answer:

From n=1 to n=2

Explanation:

Electrons in n=1 are strongly attracted to the nucleus and therefore will require great force to overcome the electrostatic force of attraction to displace them from the energy level to another.

The electrostatic force reduces as you progress to the outer energy levels.

MrRa [10]3 years ago
4 0

<u>Answer:</u>

<em>C. from n = 1 to n = 2</em>

<u>Explanation:</u>

A.

\Delta E=E_{final}-E_{initial}

\Delta E=-1312[\frac{1}{(n_f^2 )}-\frac {1}{(n_i^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{(4^2 )}-\frac {1}{(3^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{(16 )}-\frac {1}{(9)}]KJ mol^{-1}

\Delta E=-1312[0.0625-0.111]KJ mol^{-1}

\Delta E=64 KJ mol^{-1}

B.

\Delta E=E_{final}-E_{initial}

\Delta E=-1312[\frac{1}{(n_f^2 )}-\frac {1}{(n_i^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{(3^2 )}-\frac {1}{(2^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{(9 )}-\frac {1}{(4)}]KJ mol^{-1}

\Delta E=-1312[0.111-0.25]KJ mol^{-1}

\Delta E=182 KJ mol^{-1}

C.

\Delta E=E_{final}-E_{initial}

\Delta E=-1312[\frac{1}{(n_f^2 )}-\frac {1}{(n_i^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{(2^2 )}-\frac {1}{(1^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{(4)}-\frac {1}{(1)}]KJ mol^{-1}

\Delta E=-1312[0.25-1]KJ mol^{-1}

\Delta E=984 KJ mol^{-1}

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2 years ago
Give the ground-state electron configuration for silicon (SiSi) using noble-gas shorthand. Express your answer in condensed form
nydimaria [60]

Answer:

[Ne] 3s² 3p²

Explanation:

Silicon atoms have 14 electrons. The ground state electron configuration of ground state gaseous neutral silicon is 1s²2s²2p⁶3s²3p².

Using noble gas shorthand, the electronic configuration is reduced to;

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5 0
3 years ago
At STP, how many liters of oxygen are required to react completely with 3.6 liters of hydrogen to form water?
Delvig [45]
Should be 1.8L.
2 moles of hydrogen react with 1 mole of oxygen. If 2 moles of hydrogen is 3.6L, 1 mole of oxygen should be 1.8L.
7 0
3 years ago
If 23.6 g of hydrogen gas reacts with 28.3 g of nitrogen gas, what is the maximum amount of product that can be produced?
Aleonysh [2.5K]

Answer:

34.3 g NH3

Explanation:

M(H2) = 2*1 = 2 g/mol

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23.6 g H2* 1 mol/2 g = 11.8 mol H2

28.3 g N2 * 1 mol/28 g = 1.01 mol N2

                                 3H2 + N2 ------> 2NH3

from reaction         3 mol    1 mol

given                   11.8 mol    1.01 mol

We can see that H2 is given in excess, N2 is limiting reactant.

                                 3H2 + N2 ------> 2NH3

from reaction                     1 mol         2 mol

given                                 1.01 mol      x

x = 2*1.01/1= 2.02 mol NH3

2.02 mol * 17g/1 mol ≈ 34.3 g NH3

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3 years ago
What might your life be like if Mr. Fleming didn't notice that the mold killed the bacteria?
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Answer:

probably kinda weird

Explanation:

8 0
3 years ago
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