How do you do 5x10+11? Please I am d u m b
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point B is located in quadrant II (option B)
Explanation:Point A: (6, 3) = (x, y)
reflection of point A across the y axis:
The x coordinate will be negative and the y coordinate will remain the same
reflection of point A across the y axis = (-6, 3)
Attaching the graph showing the point after reflection:
Since point B is the reflection of point A.
Hence, point B is located in quadrant II (option B)
The problem statement asks for the area of the pool. We will assume that is an error, and that you want to fill in the table with the area of the walkway.
Consider a walkway of width w. The outside dimension of the walkway will be 2w plus the dimension of the pool (since there is a walk on either side). Thus, the outside dimensions of the pool and walkway are 9+2w and 12+2w yards.
The area of the pool and walkway will be
... total area = pool area + walkway = (9 + 2w)(12 + 2w) = 9·12 + 2w(9+12) +4w²
... total area = (9·12) + walkway = 9·12 + 42w + 4w²
Subtracting the pool area gives the area of the walkway as
... walkway = 42w + 4w² = 2w(2w+21)
Using this formula, we can fill in the table