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aksik [14]
2 years ago
6

How do you do 5x10+11? Please I am d u m b

Mathematics
2 answers:
stira [4]2 years ago
7 0

Answer: 61

Step-by-step explanation: 5 times 10 is 50. Add 11 to that and it is 61

jasenka [17]2 years ago
4 0
5 x 10 is 50 then 50 + 11 is 61 so I think it would be 61 ;)
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A line contains the points (3,9) and (-1,1) what is the equation of the line?
kirza4 [7]
To find the equation of a line using two given set of points, you must first find slope. To do so, we must use the slope formula:
y2 - y1 / x2 - x1 

In this case:
1 - 9 / -1 - 3 = -8 / -4 
- 8 / -4 = 2 (simplified) 

Now we can use the point-slope formula:
y - y1 = m(x - x1) 

y - 1 = 2(x + 1 )
y - 1 = 2x + 2
y = 2x + 3

In order to make 3x - y = 6 in slope intercept form, we must isolate y.

- y = -3x + 6
Note: y cannot be negative, so we'll multiply both sides by -1 
( -1 ) - y = - 3x + 6 ( -1 ) = y = 3x -6
6 0
3 years ago
Read 2 more answers
5a + 3b + c= 40<br> a-3b+2c= -10<br> 14a-2b+3c= 50
aalyn [17]

Answer:

a= 40-3b-c/5

a=-10+3b-2c

a=50+2b-3c/14

Step-by-step explanation:

5a+3b+c-(3b+c)=40-(3b+c)

5a=40-3b-c

5a/5=40/5-3b/5-c/5

a= 40-3b-c/5

a-3b+2c-(3b+2c)=-10-(-3b+2c)

a=-10+3b-2c

14a-2b+3c-(-2b+3c)=50-(-2b+3c)

14a=50+2b-3c

14a/14=50/14+2b/14-3c/14  

a=50+2b-3c/14

8 0
3 years ago
Find the volume of the solid under the plane 5x + 9y − z = 0 and above the region bounded by y = x and y = x4.
svp [43]
<span>For the plane, we have z = 5x + 9y

For the region, we first find its boundary curves' points of intersection.
x = x^4 ==> x = 0, 1.

Since x > x^4 for y in [0, 1],

The volume of the solid equals

\int\limits^1_0 { \int\limits_{x^4}^x {(5x+9y)} \, dy } \, dx = \int\limits^1_0 {\left[5xy+ \frac{9}{2} y^2\right]_{x^4}^{x}} \, dx  \\  \\ =\int\limits^1_0 {\left[\left(5x(x)+ \frac{9}{2} (x)^2\right)-\left(5x(x^4)+ \frac{9}{2} (x^4)^2\right)\right]} \, dx  \\  \\ =\int\limits^1_0 {\left(5x^2+ \frac{9}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx =\int\limits^1_0 {\left( \frac{19}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx \\  \\ =\left[ \frac{19}{6} x^3- \frac{5}{6} x^6- \frac{1}{2} x^9\right]^1_0

=\frac{19}{6} - \frac{5}{6} - \frac{1}{2} =\bold{ \frac{11}{6} \ cubic \ units}</span>
8 0
3 years ago
Find the mean of 81, 97, 99, 89, 91, 76 (round to the hundredths)
Marta_Voda [28]

Answer:

88.83

Step-by-step explanation:

To find the mean of a set of numbers is to find the average a set of numbers.

To solve for the mean you have to add all of the values together and divide that sum by the number of values there are.

Ex. 81, 97, 99, 89, 91, 76

     81 + 97 + 99 + 89 + 91 + 76 = 533

     533 / 6 = 88.83

               ↓

     (number of values)

3 0
3 years ago
Solve the equation.<br><br> –3x + 1 + 10x = x + 4
SIZIF [17.4K]

First, simplify. Combine like terms

10x - 3x = 7x

7x + 1 = x + 4

Isolate the x. Subtract x from both sides, and 1 from both sides

7x (-x) + 1 (-1) = x (-x) + 4 (-1)

7x - x = 4 - 1

Simplify

6x = 3

Isolate the x. Divide 6 from both sides

6x/6 = 3/6

x = 1/2

1/2, or 0.5 is your answer for x.

hope this helps

4 0
3 years ago
Read 2 more answers
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