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yanalaym [24]
2 years ago
10

Use to isolate the variable.

Mathematics
1 answer:
diamong [38]2 years ago
6 0
What do you need help will I don't see an question or anything
You might be interested in
I need help please please!!!
wel

Answer:

y = 91

Step-by-step explanation:

y = 5² + 10(5) + 16

y = 25 + 50 + 16

y = 91

4 0
3 years ago
A park has a large circle painted in the middle of the playground area. The circle is divided into 4 equal sections, and each se
oee [108]
First you need to find the area of the whole circle.\pi  r^{2}
The radius is given as 10, so just insert 10 into the equation of the area of a circle equation. 
Area =  \pi  10^{2}    Area =  100 \pi
Putting \pi after the 100 because that is what is commonly done. 

Because the circle is then being split into 4 equal sections, we need to find 1/4 of the area of the whole circle to find the area of one of these sections. 

Since the area of the whole circle is 100 \pi then we just divide that by 4, 
leaving us with 25\pi and that is our final answer

3 0
3 years ago
A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard
Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

\sigma=\frac{0.8}{\sqrt{37}}=0.13

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, P(z > 1.69) = 1 - P(z < 1.69)

P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0
3 years ago
One weekend, Paola started reading a book for school. She read 35 pages of the book on Saturday. On Sunday she read 15 pages an
Sidana [21]
35 + 15 x 4 = 60. Paola read 60 pages in total.
6 0
3 years ago
Researchers have concluded that a dry basin began to fill with water in 1880. the water level rose an average of 1.6 millimeters
docker41 [41]

Answer:

  1. the domain is [0,129]
  2. 112 mm
  3. 1942

Step-by-step explanation:

1. The function is good for years 1880 to 2009, 0 to 129 years after 1880. Values of x can be anything in the domain [0, 129].

__

2. 1950 -1880 = 70. The year 1950 corresponds to x=70, so the function tells us the water level rose ...

  f(70) = 1.6·70 = 112 . . . . . mm

__

3. We want to find x when f(x) = 100. That will be the solution to ...

  100 = 1.6x

  100/1.6 = x = 62.5

Then 62.5 years after 1880 is year 1942.5. The water level was 100 mm higher than in 1880 in the year 1942.

3 0
2 years ago
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