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statuscvo [17]
3 years ago
11

In the diagram shown, satellite S moves in a circular orbit around the Earth (E) in a counterclockwise direction.

Physics
1 answer:
zubka84 [21]3 years ago
6 0

The characteristics of the velocity vector used to find the results for the direction of acceleration and velocity are:

  • Acceleration is towards the center of the circle
  • The velocity is tangent to the circle counterclockwise.

Newton's Second Law establishes a relationship between force, mass and acceleration of bodies.

<h3>Centripetal acceleration. </h3>

In the case of circular motion there is a constant change in the direction of the velocity vector, even when its module remains constant, this change in direction points towards the center of the circle, so that the module is constant.

They indicate that the satellite is moving counterclockwise, therefore the speed must go to the left (counterclockwise) tangential to the circle.

In conclusion using the characteristics of the velocity vector we can find the results for the direction of acceleration and velocity are:

  • Acceleration is towards the center of the circle
  • The velocity is tangent to the circle counterclockwise.

Learn more about centripetal acceleration here: brainly.com/question/25243603

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You should be extra careful during the hours of sunrise, sunset, and nighttime because
skelet666 [1.2K]

Poor visibility, difficulties in colour perception, lessened colour contrast vision due to darker shadows and reduced peripheral vision, these are the reasons why one has to be extra careful while driving during hours of sunrise, sunset and night time.  

<h3><u> Explanation: </u></h3>

Sunrise, sunset and night time are parts of the day with minimal or absolutely no presence of sunlight. To safely navigate roads, we require enough light in order to detect presence of other vehicles, signs and pedestrians. Less sunlight during sunrise and sunset light the sky but makes the roads and vehicles have a darker, less bright view. The contrast between colours is the least, making it difficult to identify objects and see clearly.  

A rising or a setting sun can also lead to glares on the driver’s view and thus obstruct it. Since a change in ambient light is observed, our eyes need to adjust with this change and this isn’t spontaneous. Night time driving has headlight glares from approaching vehicles and reduced surrounding visibility. The eyes switching for vision adaptability from dark to bright light if vehicles approach and pass by is not a quick action. Hence the driver’s vision is compromised in every such case and this may lead to accidents.  

7 0
4 years ago
Jane does 5 joules of work when she closes her bedroom window. She applies a force of 6 newtons to do the job. How far does she
insens350 [35]

<u>Statement</u><u>:</u>

Jane does 5 joules of work when she closes her bedroom window. She applies a force of 6 newtons to do the job.

<u>To </u><u>find </u><u>out:</u>

The displacement of the window when she pulled it.

<u>Solution</u><u>:</u>

  • Work done (W) = 5 J
  • Force (F) = 6 N
  • Let the displacement of the window be s.
  • We know, the formula of work done, i.e., W = Fs
  • Putting the values in the above formula, we get
  • 5 J = 6 N × s
  • or, s = (5 ÷ 6) m
  • or, s = 0.83 m

<u>Answer</u><u>:</u>

She pulls the window by 0.83 m.

Hope you could understand.

If you have any query, feel free to ask.

4 0
3 years ago
plz i need help fast................a motion along a straight line with a constant increase in velocity is ?​
Monica [59]

Answer:

uniform acceleration

Explanation:

The definition for uniform acceleration is:

if an object travels in  a straight line and its velocity increases or decreases by equal amounts in equal intervals of time, then the acceleration is said to be uniform.

Hope this helps.

Good Luck

8 0
4 years ago
Read 2 more answers
All digits shown on the measuring device, plus one estimated digit are considered____
erastovalidia [21]
I think the answer is significant
4 0
3 years ago
NASA is giving serious consideration to the concept of solar sailing. A solar sailcraft uses a large, lowmass sail and the energ
Elan Coil [88]

Answer:

a) the reflective surface has twice the energy transfer

b) A = 1.3 10²⁷ km²

c) the energy emitted by the sun is distributed in a sphere that depends on the square of the distance, and the gravitational force depends on the square of the distance

Explanation:

a) The pressure exerted on the candle is related to the variation of the momentum

          P = \frac{1}{c} \ \frac{dp}{dt}

in a case of absorption (inelastic shock) all the energy is absorbed therefore the pressure is

          P = \frac{1}{c} \ \frac{dp}{dt}

in the case of reflection (elastic shock) an energy is absorbed by absorbing the light and then by action and reaction the same energy is absorbed in the reflected light

          P = 2  \frac{1}{c} \ \frac{dp}{dt}

In conclusion, the reflective surface has twice the energy transfer.

             

b) pressure is defined with force per unit area

           P = F / A

           F = P A

this force must be greater than the gravitational force of attraction of the sun

           Fg = G m Ms / r²

let's look for the case that the two forces are equal

           F = Fg

           P A_sail = G m Ms = r²

suppose a fully reflective sail

           2 \frac{S}{c}  \ A_{sail} = G \frac{m M_s}{r^2}

           

The pointing vector is the power delivered per unit area

           S = I = P / A

where A is the area of ​​the sphere where the is distributed by the sun

            A = 4π r²

we substitute

            \frac{2P}{c} \ \frac{A_{sail}}{4 \pi   r^2} = G \frac{m M_s}{r^2}

            \frac{1}{2 \pi \ c } A_{sail} = G m M_s

            A = G  m M_s 2π c

let's calculate

            A = 6.67 10⁻¹¹  10000 2 10³⁰ 2π  3 10⁸

            A = 1,257 10³³ m²

let's reduce to km²

            A = 1.3 10³³ m² (1km / 10³ m) ²

            A = 1.3 10²⁷ km²

c) The size of the candle is independent of the distance to the sun because the energy emitted by the sun is distributed in a sphere that depends on the square of the distance, and the gravitational force depends on the square of the distance, therefore the two dependencies are canceled.

8 0
3 years ago
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