All categories

2 years ago

In the diagram shown, satellite S moves in a circular orbit around the Earth (E) in a counterclockwise direction.

Physics

1 answer:

zubka84 [21]2 years ago

6 0

The characteristics of the velocity vector used to find the results for the direction of acceleration and velocity are:

Acceleration is towards the center of the circle

The velocity is tangent to the circle counterclockwise.

Newton's Second Law establishes a relationship between force, mass and acceleration of bodies.

<h3>Centripetal acceleration. </h3>

In the case of circular motion there is a constant change in the direction of the velocity vector, even when its module remains constant, this change in direction points towards the center of the circle, so that the module is constant.

They indicate that the satellite is moving counterclockwise, therefore the speed must go to the left (counterclockwise) tangential to the circle.

In conclusion using the characteristics of the velocity vector we can find the results for the direction of acceleration and velocity are:

Acceleration is towards the center of the circle

The velocity is tangent to the circle counterclockwise.

Learn more about centripetal acceleration here: brainly.com/question/25243603

You might be interested in

What is the momentum of a 1400 kg car traveling at 25 m/s?

sveticcg [70]

<h2>Hello</h2>

The answer is:

$35000Kg.\frac{m}{s}=35000N$

Momentum is the quantity of movement of an object, and it's calculated using the mass and the velocity of the object. Momentum is expressed by the following formula:

$p=m*v$

Where:

$m=mass\\v=velocity$

So, calculating we have:

$p=m*v=1400Kg*\frac{25m}{s}=35000Kg.\frac{m}{s}=35000N$

Remember,

$1N=1Kg.\frac{m}{s}$

Have a nice day!

5 0

3 years ago

Read 2 more answers

PLEASE HELP ITS RLLY URGENT PLEASE:((((

Sergio [31]

Answer:

1. A satellite is an object which has been sent into space in order to collect information or to be part of a communications system. Satellites move continually round the Earth or around another planet.

2. red giant

3.red giant.

Explanation:

4 0

3 years ago

Read 2 more answers

Can anyone please help me with answering this question? : An accelerating (speeding up) body has a Net Force acting in the direc

Katarina [22]

That's true.

Netwon's second law states that the resultant of the forces F acting on a body is equal to the product between its mass m and its acceleration a:
$\sum F = ma$
This means that if the net force acting on an object is different from zero (term on the left), than the acceleration of the object (term on the right) must be different from zero as well, and therefore the body is accelerating.

In particular, both F and a in the equation are vectors: this means that if the acceleration is positive, F and a have the same direction. In this problem, the acceleration is positive (because the object is speeding up), therefore the force and the acceleration have same direction.

7 0

3 years ago

If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 64 ft/sec, its height after t seconds

stepan [7]

Answer:

a) $s_{max} = 96\,ft$ , b) $v(4.449\,s) = -78.368\,\frac{ft}{s}$

Explanation:

a) The maximum height is obtained with the help of the First and Second Derivative Tests:

First Derivative

$v(t) = 64 - 32\cdot t$

$64 - 32\cdot t = 0$

$t = 2\,s$

Second Derivative

$a(t) = -32$ (absolute maximum)

The maximum height reached by the ball is:

$s (2\,s) = 32 + 64\cdot (2\,s) - 16\cdot (2\,s)^{2}$

$s_{max} = 96\,ft$

b) The time required by the ball to hit the ground is:

$32+64\cdot t - 16\cdot t^{2} = 0$

$-16\cdot (t^{2}-4\cdot t - 2) = 0$

$t^{2}-4\cdot t - 2 = 0$

$(t -4.449)\cdot (t+0.449)\approx 0$

Just one root offers a solution that is physically reasonable:

$t = 4.449\,s$

The velocity of the ball when it hits the ground is:

$v(4.449\,s) = 64 - 32\cdot (4.449\,s)$

$v(4.449\,s) = -78.368\,\frac{ft}{s}$

6 0

3 years ago

Read 2 more answers

So far in your life, you may have assumed that as you are sitting in your chair right now, you are not accelerating. However, th

shutvik [7]

Answer:

Answer is explained in the explanation section.

Explanation:

Solution:

For this to find, we need to calculate the centripetal acceleration on the equator.

The centripetal acceleration of the equator:

a = 4 $\pi ^{2}$ RcosФ/ $T^{2}$ ,

where,

R is the radius of the earth

R = 6378 KM = 6.3 x $10^{6}$ and

T is the time period

T = 24 h = 86164.1 s

At Equator, Ф = 0°

So, CosФ = 1

Hence,

a = 4 $\pi ^{2}$ R/ $T^{2}$

By plugging in the values, we get:

a = 4 x ( $3.14^{2}$ ) x (6.3 x $10^{6}$ ) / $86164.1^{2}$

a = 0.03 m/ $s^{2}$

Hence, this is the centripetal acceleration on the equator. And we also know that, acceleration due to gravity is 9.8 m/ $s^{2}$ which is very higher than the centripetal acceleration on the equator.

B) Normal force exerted by chair will always be equal and opposite to the mass times gravitational acceleration (F = mg). Otherwise, I would be thrown away from chair in case the normal force is not equal and opposite or I would be drag down to the earth due to greater mass times gravitational acceleration. Hence, both are equal and opposite.

C) Of course, this is not a lie, it is true because the acceleration due to gravity is 9.8 m/ $s^{2}$ and as we calculated the acceleration on the equator is 0.03 m/ $s^{2}$ which way too low to experience.

For percentage difference,

9.8 - 0.03 = 9.77

So, % diff = (9.8 - 9.77)/9.8 x 100

% diff = 0.00306 x 100

% diff = 0.306%

Obviously, this is way too low to experience.

D) With the help of same formula as discussed above, we have:

a = 4 $\pi ^{2}$ RcosФ/ $T^{2}$ ,

Here, Ф = 44.4°

Just putting the values. we get

a = 0.0241 m/ $s^{2}$

Acceleration while sitting in my chair.

6 0

2 years ago