Can anyone please help me with answering this question? : An accelerating (speeding up) body has a Net Force acting in the direc
1 answer:
That's true.
Netwon's second law states that the resultant of the forces F acting on a body is equal to the product between its mass m and its acceleration a:
This means that if the net force acting on an object is different from zero (term on the left), than the acceleration of the object (term on the right) must be different from zero as well, and therefore the body is accelerating.
In particular, both F and a in the equation are vectors: this means that if the acceleration is positive, F and a have the same direction. In this problem, the acceleration is positive (because the object is speeding up), therefore the force and the acceleration have same direction.
Netwon's second law states that the resultant of the forces F acting on a body is equal to the product between its mass m and its acceleration a:
This means that if the net force acting on an object is different from zero (term on the left), than the acceleration of the object (term on the right) must be different from zero as well, and therefore the body is accelerating.
In particular, both F and a in the equation are vectors: this means that if the acceleration is positive, F and a have the same direction. In this problem, the acceleration is positive (because the object is speeding up), therefore the force and the acceleration have same direction.
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Answer:
(a) Time t = 16.46 sec
(b) Time t =13.466 sec
(c) Deceleration =
Explanation:
(a) As the train starts from rest its initial velocity u = 0 m/sec
Acceleration
Final speed v = 80 km/hr
From first equation of motion v =u+at
So
(b) Now initial speed u = 22.22 m/sec
As finally train comes to rest so final speed v=0 m/sec
Deceleration
So
(c) We have given that initial velocity = 80 km/hr = 22.22 m/sec
Final velocity v = 0 m/sec
Time t = 8.30 sec
So acceleration is given by
As acceleration is negative so it is a deceleration