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3 years ago

Identify the conditions for an inelastic collision in a closed system. Check all that apply.

Physics

2 answers:

jeyben [28]3 years ago

6 0

Answer: Energy is conserved.

Momentum is conserved

One object may be stationary before an inelastic collision.

Explanation:

goldfiish [28.3K]3 years ago

3 0

teo objects hit and stick together

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A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.7 m/s rel

mafiozo [28]

Here it is given that speed of migrating Robin is 12 m/s relative to air

so we can say that

$\vec v_{ra} = 12 m/s$ North

so it will be

Let North direction is along Y axis and East direction is along X axis

$\vec v_{ra} = 12\hat j$

also it is given that speed of air is 6.7 m/s relative to ground

$\vec v_a = 6.7 \hat i$

now as we know by the concept of relative motion

$\vec v_{ab} = \vec v_a - \vec v_b$

$\vec v_{ra} = \vec v_r - \vec v_a$

now by rearranging the terms

$\vec v_r = \vec v_{ra} + \vec v_a$

$\vec v_r = 12 \hat j + 6.7 \hat i$

now we need to find the speed of Robin which means we need to find the magnitude of its velocity which we found above

So here we will say

$v_r = \sqrt{12^2 + 6.7^2}$

$v_r = 13.7 m/s$

so the net speed of Robin with respect to ground will be 13.7 m/s

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3 years ago

Why bananas are curved

Vinil7 [7]

Because they built:different

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3 years ago

Read 2 more answers

Preschool girls and boys do not differ in the amount of muscle they have<br> 1) True<br> 2) False

Marina86 [1]

Explanation:

False...............

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3 years ago

An electric power plant uses energy from burning coal to generate steam at 450∘C. The plant is cooled by 20∘C water from a nearb

Goryan [66]

Answer:

40 MJ (D)

Explanation:

Quantity of heat (Qh) = 100 MJ

temperature of steam (Th) = 450°c = 450 + 273 = 723 K

emperature of water (TI) = 20 °c = 20 + 273 = 293 k

efficiency = (Qh-Qi)/Qh = (Th-Ti)/Th

$\frac{100x10x^{6}-Qi }{100x10^{6}} = \frac{723-293}{723}$

$100x10^{6}$ - Qi= 0.5947 x $100 x 10 ^{6}$

$100x10^{6}$ - (0.5947 x $100x10^{6}$ ) = Qi

Qi = 40.5 MJ equivalent to 40 MJ (D)

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3 years ago

You do a certain amount of work on an object initially at rest, and all the work goes into increasing the object’s speed. If you

EleoNora [17]

Answer:

$\sqrt{2}v$

Explanation:

The work done on the object at rest is all converted into kinetic energy, so we can write

$W=\frac{1}{2}mv^2$

Or, re-arranging for v,

$v=\sqrt{\frac{2W}{m}}$

where

v is the final speed of the object

W is the work done

m is the object's mass

If the work done on the object is doubled, we have W' = 2W. Substituting into the previous formula, we can find the new final speed of the object:

$v'=\sqrt{\frac{2W'}{m}}=\sqrt{\frac{2(2W)}{m}}=\sqrt{2}\sqrt{\frac{2W}{m}}=\sqrt{2}v$

So, the new speed of the object is $\sqrt{2}v$ .

3 0

3 years ago