PLEASE HELP ITS RLLY URGENT PLEASE:((((

A crane is lifting a 500 lb piano with a velocity of 2fts''. Express the power of the crane in hp. (1 hp = 550ft-lbs)

Sonja [21]

Answer:

goalindia

goalindiaGiven:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kg

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 W

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64⇒ v = 0.61 m/s

goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64⇒ v = 0.61 m/s- So, the velocity of the car will be 0.61❤

6 0

2 years ago

Un auto se mueve con velocidad constante de 20 m/s y la mantiene durante 20 s. Después se le aplica una aceleración constante y

pentagon [3]

Answer:

26.67 s

Explanation:

v = Velocidad final = 40 m/s

u = Velocidad inicial = 20 m/s

$t_1$ = Tiempo inicial = 20 s

$t_2$ = Tiempo empleado durante la aceleración

a = Aceleración

s = Desplazamiento del automóvil durante la aceleración = 200 m

De las ecuaciones lineales de movimiento tenemos

$v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{40^2-20^2}{2\times 200}\\\Rightarrow a=3\ \text{m/s}^2$

$v=u+at_2\\\Rightarrow t_2=\dfrac{v-u}{a}\\\Rightarrow t_2=\dfrac{40-20}{3}\\\Rightarrow t_2=6.67\ \text{s}$

El tiempo necesario para acelerar es 6.67 s

El tiempo total necesario para toda la ruta es $t=t_1+t_2=20+6.67=26.67\ \text{s}$ .

4 0

3 years ago

If you mix 100 g of ice at 0 ∘c with 100 g of boiling water at 100 ∘c in a perfectly insulated container, the final stabilized t

loris [4]

The final stabilized temperature will be between 0 °C and 50 °C.

<h3>Calorimetry:</h3>

The enthalpy of fusion of ice is 334 J/g. The specific heat of water is 4.2 J/g.

To cool 100 g of water from 100 °C to 0 °C would require the removal of

4.2 x 100 x 100 = 42000 J.

To melt the ice would require the addition of

334 x 100 = 33400 J

∴ 42000 > 33400 thus you can melt all the ice and have some heat to spare, specifically 42000 - 33400 = 8600 J

Now use this to warm up 100+100 = 200 g of water at 0 °C

The final stabilized temperature;

8600 / (200 x 4.2) = 10.23 °C

Therefore, the final stabilized temperature is 10.23 °C

Learn more about Calorimetry here:

brainly.com/question/1989313

#SPJ4

4 0

2 years ago

When we look up in the sky the Sun appears about as big as the moon; however, we know that the Sun is much further away. Given t

Nady [450]

Answer: well since you can fit one million Earths in the sun just multiply.

hope this helps happy thanksgiving ;)

8 0

3 years ago

7) The acceleration of gravity on the Moon is only one-sixth of that on Earth. If you hit a baseball on the Moon with the same e

rusak2 [61]

Answer:

The acceleration of gravity on the Moon is only one-sixth of that on Earth. If we hit a baseball on the moon with the same effort(and at the speed and angle)that we would on earth, the ball would land 6 times as far. The ball on the moon will cover 6 times more distance than Earth.

Explanation:

Speed=distance travelled/Time required speed

Speed=d/t

Acceleration of gravity on earth=9.8 m/s^2

Acceleration of gravity on Moon=1.62 m/s^2

So the maximum height of ball will be the ration of these both gravity.

4 0

3 years ago