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-Dominant- [34]
2 years ago
10

Question 1 of 10

Mathematics
1 answer:
xeze [42]2 years ago
5 0

Answer:

D.

Step-by-step explanation:

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What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 > 15?
jolli1 [7]

Answer:

A. d ≤ –7 or d > 8.

Step-by-step explanation:

Given  : 2d + 3 ≤ –11 or 3d – 9 > 15.

To find : What are the solutions of the compound inequality .

Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.

For  2d + 3 ≤ –11

On subtracting both sides by 3

2d  ≤ –11 - 3 .

2d  ≤ –14.

On dividing both sides by 2 .

d  ≤ –7.

For  3d – 9 > 15.

On adding both sides by 9.

3d > 15 + 9 .

3d > 24 .

On dividing both sides by 3 .

d > 8 .

So, A. d ≤ –7 or d > 8.

Therefore,  A. d ≤ –7 or d > 8.

7 0
3 years ago
Sherri bought her daughter a microscope for her birthday. If it cost $79.99 plus 5% tax, how much did she have to pay for it?
Eduardwww [97]

Answer:

Around 84 dollars

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Suppose that you believe that contractor 1 is twice as likely to win as contractor 3 and that contractor 2 is three times as lik
Ray Of Light [21]

Answer:

probability that contractor 1,2 and 3 win is 33%,50% and 17% respectively

Step-by-step explanation:

assuming that there are no other contractors then:

probability that 1 , 2 or 3 win = 1

denoting as X= probability that contractor 3 wins , then assuming that only one wins , we have

probability that 1 , 2 or 3 win = 1

probability that contractor 1 wins + probability that contractor 2 wins + probability that contractor 3 wins = 1

2*P(X) + 3*P(X) + P(X) = 1

6*P(X) = 1

P(X) =1/6

then

-probability that contractor 1 wins = 2/6 (33%)

-probability that contractor 3 wins = 3/6 (50%)

-probability that contractor 3 wins = 1/6 (17%)

3 0
2 years ago
Evaluate the function g(x) = 8x + 16 when x = -3,0, and 8.<br> g(-3) =<br> ) 0<br> g(0) =<br> 9(8) =
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

7 0
2 years ago
I don't know how to do this?
miskamm [114]
Do you know foil? FOIL= First,Outside,Inside, and Last

7 0
3 years ago
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