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2 years ago

This is for the real ones- find the missing side x. Giving brainliest.

Mathematics

1 answer:

Luba_88 [7]2 years ago

7 0

Answer: The answer is X equals 10 2/3.

Explanation: This is a proportion. We see that the right rectangle when turned to the right is proportional to the left rectangle. On the left rectangle, the smaller side is 6 ft, and the larger side is 16 ft. On the right rectangle, the smaller side is 4 ft. 6 ÷ 1.5 = 4, therefore 16 ÷ 1.5 = 10 2/3.

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Find the value of x in the solution 8x-6>12+x

VARVARA [1.3K]

Answer: x > 18/7

Step-by-step explanation:

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3 years ago

Which function passes through the points (2,3) and (4,4)?

Pie

A(2;3), B(4;4)
$y=ax+b$
$a=\dfrac{4-3}{4-2}=\dfrac{1}{2}$
$3=\dfrac{1}{2}*2+b$
$3=1+b$
$b=2$

$y=\dfrac{1}{2}x+2$

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3 years ago

Don't know where to start , please show steps if you do it!

Nutka1998 [239]

Answer:

Step-by-step explanation:

$\frac{EF}{DF} =sin~26\\EF=DF *sin~26\\=4.5*0.44\\\approx ~1.98$

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3 years ago

Read 2 more answers

In the trapezoid ABCD (AB∥CD) point M∈AD, so that AM:MD=3:5. Line L ∥AB and going through point M intersects diagonal AC and leg

siniylev [52]

Answer:

$\dfrac{AP}{PC}=\dfrac{3}{5}$

$\dfrac{BN}{CN}=\dfrac{3}{5}$

Step-by-step explanation:

Consider triangles AMP and ADC. In these triangles,

angle A is the common angle, so $\angle MAP\cong \angle DAC$ by reflexive property;
angles AMP and ADC are congruent as corresponding angles when two parallel lines MP and CD are cut by transversal AD.

Hence, triangles AMP and ADC are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

$\dfrac{AM}{AD}=\dfrac{AP}{AC}\\ \\\dfrac{3x}{3x+5x}=\dfrac{AP}{AC}\\ \\\dfrac{AP}{AC}=\dfrac{3}{8}\Rightarrow AP=\dfrac{3}{8}AC\\ \\PC=AC-AP=AC-\dfrac{3}{8}AC=\dfrac{5}{8}AC,$

$\dfrac{AP}{PC}=\dfrac{\frac{3}{8}AC}{\frac{5}{8}AC}=\dfrac{3}{5}$

Consider triangles ACB and PCN. In these triangles,

angle C is the common angle, so $\angle ACB\cong \angle PCN$ by reflexive property;
angles ABC and PCN are congruent as corresponding angles when two parallel lines PN and AB are cut by transversal BC.

Hence, triangles ACB and PCN are similar by AA similarity theorem.

Similar triangles have proportional corresponding sides, thus

$\dfrac{CP}{AP}=\dfrac{CN}{CB}\\ \\\dfrac{5x}{3x+5x}=\dfrac{CN}{CB}\\ \\\dfrac{CN}{CB}=\dfrac{5}{8}\Rightarrow CN=\dfrac{5}{8}CB\\ \\BN=BC-CN=BC-\dfrac{5}{8}BC=\dfrac{3}{8}BC,$

$\dfrac{BN}{CN}=\dfrac{\frac{3}{8}BC}{\frac{5}{8}BC}=\dfrac{3}{5}$

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3 years ago

State the slope of a line parallel to <br> y = 3.75

Alex73 [517]

m = 0

Step-by-step explanation:

If it's written in y =mx + c form, x is 0 and so is m.

Thus, m should be 0

8 0

4 years ago