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Vikki [24]
2 years ago
6

Use the remainder theorem to show that (x+1) is a factor of f(x)=2x^3-7x^2-5x+4

Mathematics
1 answer:
Nitella [24]2 years ago
3 0

well, the remainder theorem says that if the polynomial f(x) has a factor of (x-a), then if we just plug in the "a" in f(x) it'll gives a remainder, assuming (x-a) is indeed a factor, then that remainder must be 0, so if f(a) = 0 then indeed (x-a) is a factor of f(x).  After all that mumble jumble, let's proceed, we have (x+1), that means [ x - (-1) ], so if we plug in -1 in f(x), we should get 0, or f(-1) = 0, let's see if that's true.

\begin{array}{llrll} f(-1)&=&2(-1)^3-7(-1)^2-5(-1)+4\\\\ &&2(-1)-7(1)-5(-1)+4\\\\ &&-2-7+5+4\\\\ &&-9+9\\ &&0&~~\checkmark \end{array}

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Step-by-step explanation:

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4 0
3 years ago
I REALLY NEED HELP PLEASE!!  
disa [49]


part A)

\bf \begin{array}{ccllll}
hours(x)&velocity(y)\\
-----&-----\\
1&6\\
3&2
\end{array}\\\\
-------------------------------\\\\


\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 1}}\quad ,&{{ 6}})\quad 
%   (c,d)
&({{ 3}}\quad ,&{{ 2}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{2-6}{3-1}\implies \cfrac{-4}{2}\implies -2

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\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-6=-2x+2\implies y=-2x+2+6\implies \boxed{y=-2x+8}

part B)

well, we know y = -2x+8.... so.. what's the runner's velocity after 5hours? well, x = 5, thus y = -2(5) +8 ---> y = -2

to graph it, well, is a LINEar equation, meaning the graph is a LINE, and to graph a line, all you need is two points, and by now, you have more than two.. so graph it away.
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3 years ago
Whats 5-2y=3x in standard form?
Luda [366]

5-2y=3x \\\\3x+2y=5

4 0
4 years ago
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loris [4]

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3 years ago
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mario62 [17]

Answer:

<h2>0</h2>

solution,

(\frac{1}{7} ) ^{3a + 3}  =  {343}^{a - 1}  \\ or \: ( {7}^{ - 1} ) ^{3a + 3}  =  {(7}^{3} ) ^{a - 1}  \\ or \: (7) ^{ - 3a - 3}  =  {(7)}^{3a - 3}  \\ or \:  - 3a - 3 = 3a - 33 \\ or \:  - 3a - 3a =  - 3 + 3 \\ or \:  - 6a =  0 \\  \: a = 0

hope this helps..

Good luck on your assignment..

3 0
3 years ago
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