Use the remainder theorem to show that (x+1) is a factor of f(x)=2x^3-7x^2-5x+4
1 answer:
well, the remainder theorem says that if the polynomial f(x) has a factor of (x-a), then if we just plug in the "a" in f(x) it'll gives a remainder, assuming (x-a) is indeed a factor, then that remainder must be 0, so if f(a) = 0 then indeed (x-a) is a factor of f(x). After all that mumble jumble, let's proceed, we have (x+1), that means [ x - (-1) ], so if we plug in -1 in f(x), we should get 0, or f(-1) = 0, let's see if that's true.
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Answer:
X''(2, -5), Y''(3, -3)
Step-by-step explanation:
You know that reflection in the x-axis changes the sign of the y-coordinate. Points that used to be above the axis are now below by the same amount, and vice versa.
Rotation counterclockwise by 270° is the same as clockwise rotation by 90°. That maps the coordinates like this:
(x, y) ⇒ (y, -x)
The two transformations together give you ...
(x, y) ⇒ (x, -y) ⇒ (-y, -x) . . . . . . . . equivalent to reflection across y=-x.
Using this mapping, we have ...
X(5, -2) ⇒ X''(2, -5)
Y(3, -3) ⇒ Y''(3, -3) . . . . . . on the equivalent line of reflection, so invariant
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The attachment shows the original segment in red, the reflected segment in purple, and the rotated segment in blue. The equivalent line of reflection is shown as a dashed green line.
