The equation of the hyperbola is : ![\frac{x^{2}}{48^2} - \frac{y^{2}}{14^2} = 1](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%5E%7B2%7D%7D%7B48%5E2%7D%20%20-%20%5Cfrac%7By%5E%7B2%7D%7D%7B14%5E2%7D%20%20%3D%201%20)
The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)
As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin:
The distance from center to focus is 'c' and here focus is at (-50,0)
So, c= 50
Now if the distance from center to the directrix line is 'd', then
![d= \frac{a^{2}}{c}](https://tex.z-dn.net/?f=%20d%3D%20%5Cfrac%7Ba%5E%7B2%7D%7D%7Bc%7D%20%20%20)
Here the directrix line is given as : x= 2304/50
Thus, ![\frac{a^{2}}{c} = \frac{2304}{50}](https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%5E%7B2%7D%7D%7Bc%7D%20%20%3D%20%5Cfrac%7B2304%7D%7B50%7D%20%20)
⇒ ![\frac{a^{2}}{50} = \frac{2304}{50}](https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%5E%7B2%7D%7D%7B50%7D%20%20%3D%20%5Cfrac%7B2304%7D%7B50%7D%20%20)
⇒ a² = 2304
⇒ a = √2304 = 48
For hyperbola, b² = c² - a²
⇒ b² = 50² - 48² (By plugging c=50 and a = 48)
⇒ b² = 2500 - 2304
⇒ b² = 196
⇒ b = √196 = 14
So, the equation of the hyperbola is : ![\frac{x^{2}}{48^2} - \frac{y^{2}}{14^2} = 1](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%5E%7B2%7D%7D%7B48%5E2%7D%20%20-%20%5Cfrac%7By%5E%7B2%7D%7D%7B14%5E2%7D%20%20%3D%201%20)
Counting by Tens with numbers
10, 20, 30, 40, 50, 60, 70, 80, 90
Counting by Tens with words
ten, twenty, thirty, forty, fifty, sixty, seventy, eighty, ninety, one hundred
Number Patterns when counting by Tens
When you count by tens the numbers create a pattern. All the numbers end with a zero. The first digits are just like the numbers when you count (1, 2, 3, 4, 5, etc.). This pattern gives the numbers 10, 20, 30, 40, 50, etc.
found from: http://www.aaamath.com/k4c_cox1.htm
<span>C and B are *candidates* for being the correct solution
because f(2) = 4 for both.
</span>
A is the correct solution because f(3)=6
The answer for this would be 5.78 - angular velocity , I think