9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
__
4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
__
If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
Answer:
178
Step-by-step explanation:
1246 over a week, (1246/7) in a day. 178 rocks a day
The correct answer is C) t₁ = 375,

.
From the general form,

, we must work backward to find t₁.
The general form is derived from the explicit form, which is

. We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

Using the products of exponents, we can "split up" the exponent:

We know that 5⁻¹ = 1/5, so this gives us

Comparing this to our general form, we see that

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375
The recursive formula for a geometric sequence is given by

, while we must state what t₁ is; this gives us
<span>5.17490 rounded to the nearest thousandth is 5.175</span>