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2 years ago

A bus is traveling 54 miles per hour. Use this information to fill in the table.

Mathematics

2 answers:

mixer [17]2 years ago

8 0

Answer:

- In this problem, 27 may represent either 27 miles or 27 hours.

The bus travels 54 miles in 1 hour. You can scale the rate down to find how far the bus travels in 0.5 hour.

- In this problem, 1 may represent either 1 mile or 1 hour.

54 miles per hour means 54 miles in 1 hour.

This spot is for how many hours it would take the bus to travel 54 miles.

- In this problem, 2 may represent either 2 miles or 2 hours.

The bus travels 54 miles in 1 hour. You can scale the rate up to find how many hours it would take the bus to travel 108 miles.

- In this problem, 135 may represent either 135 miles or 135 hours.

The bus travels 54 miles in 1 hour. You can scale the rate up to find how many miles the bus travels in 2.5 hours.

Hope this help you! :)

ANTONII [103]2 years ago

6 0

Nice....

I am from India server...

username : Redplanet

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Evaluate -6+(-12) =(-6).

padilas [110]

Cancelling out both the -6 we get 12=0 which is not true, hence the equation is incorrect.

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3 years ago

you have 3.75 to spend at a vending machine. You want to buy at least three health bars. Regualr health bars cost 0.75 each and

DedPeter [7]

Answer:

Let x be the number of regular health bars you buy and y the number of strawberry health bars you buy. Then:

0.75x+1.25y=3.75

x+y>=3

Step-by-step explanation:

For the first equation, we have to assume that you will spend all of your money, otherwise it becomes an inequation. The money you spend on regular bars is 0.75x dollars and the money you spend on strawberry bars is 1.25y, so if you spend your 3.75 dollars on the bars, then 0.75x+1.25y=3.75.

For the second, you will always buy x+y health bars, regular and strawberry. There isn't enough information to make this into a equation, the only thing we can deduce is the inequation x+y>=3.

If we also assume that x and y are integers (we can't buy half-bars or one-fourth of a bar) then the minimum number of bars we can buy is 3 (3 strawberry bars) and the maximum is 5 bars (5 regular bars). x+y must be an integer too, so the possibilities for the second equation are x+y=3, x+y=4 and x+y=5. There is a finite number of solutions in any case.

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3 years ago

A telephone company charges a fixed monthly rate plus a rate per minute of usage. The company charges $135 for 100 minutes of us

Licemer1 [7]

Draw a graph which joins the points (100, 135) and (500, 375) and has a slope = 0.6 is the one among the following that can best describe the steps to draw the graph of y against x. The correct option among all the options that are given in the question is the second option or option "B". I hope it helps you.

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3 years ago

Read 2 more answers

can you please help me find the area. I put 141 but it says that i am wrong. Can anybody help and say what i did wrong.

Sphinxa [80]

Answer:

3120 think

Step-by-step explanation:

i just did 3x8x10x13

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3 years ago

CAN SOMEONE HELP ME IN THIS INTEGRAL QUESTION PLS

finlep [7]

Due to the symmetry of the paraboloid about the z-axis, you can treat this is a surface of revolution. Consider the curve $y=x^2$ , with $1\le x\le2$ , and revolve it about the y-axis. The area of the resulting surface is then

$\displaystyle2\pi\int_1^2x\sqrt{1+(y')^2}\,\mathrm dx=2\pi\int_1^2x\sqrt{1+4x^2}\,\mathrm dx=\frac{(17^{3/2}-5^{3/2})\pi}6$

But perhaps you'd like the surface integral treatment. Parameterize the surface by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u^2\,\vec k$

with $1\le u\le2$ and $0\le v\le2\pi$ , where the third component follows from

$z=x^2+y^2=(u\cos v)^2+(u\sin v)^2=u^2$

Take the normal vector to the surface to be

$\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial u}=-2u^2\cos v\,\vec\imath-2u^2\sin v\,\vec\jmath+u\,\vec k$

The precise order of the partial derivatives doesn't matter, because we're ultimately interested in the magnitude of the cross product:

$\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|=u\sqrt{1+4u^2}$

Then the area of the surface is

$\displaystyle\int_0^{2\pi}\int_1^2\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\int_0^{2\pi}\int_1^2u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv$

which reduces to the integral used in the surface-of-revolution setup.

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3 years ago