X/5=y/3 and 12/y=4/5 What is x and what is y?

The average cost of a compact car at a certain dealership over the last ten years has ranged from $14,000 to $18,500. Suppose yo

mezya [45]

Answer:

Part (A): The scale of y: 1 interval being equal to 500 units and from 14,000 to 18,500.

Part (B): The good interval to use for the y-axis should be 1 to 10.

Step-by-step explanation:

Consider the provided information.

As we know the X axis represents the independent variable, since years are the independent variable. So, X axis represents the years.

Y axis represents the dependent variable, since average cost is dependent variable. So, Y axis represents the average cost.

Part (A) what is a good scale to use for the y-axis?

It is given that range is from $14,000 to $18,500.

So, 1 interval being equal to 500 units, so that it will suitable for 18,500.

The scale of y should be 14,000 to 18,500 as 14,000 is the starting average cost and 18,500 is the last average cost.

Part (b) what is a good interval to use for the y-axis?

The scale for x should be 1 year. As It should start from 1 to 10.

The good interval to use for the y-axis should be 1 to 10.

The required scale is shown in figure,

8 0

3 years ago

HELP I need to fine the slope-intercept form. Please it’s a timed assignment I only have two try’s and I already used one

barxatty [35]

Answer:

5. y = -1/2x + 6

6. y = 1/2x + 150

7. y = 10x + 20

8. y = 25x

Step-by-step explanation:

Look at the y-intercept and eliminate the answers you dont need.

Then find the slope of each.

8 0

2 years ago

A college counselor is interested in estimating how many credits a student typically enrolls in each semester. The counselor dec

Ket [755]

Answer:

(a) The usual load is not 13 credits.

(b) The probability that a a student at this college takes 16 or more credits is 0.1093.

Step-by-step explanation:

According to the Central limit theorem, if a large sample (n ≥ 30) is selected from an unknown population then the sampling distribution of sample mean follows a Normal distribution.

The information provided is:

$Min.=8\\Q_{1}=13\\Median=14\\Mean=13.65\\SD=1.91\\Q_{3}=15\\Max.=18$

The sample size is, n = 100.

The sample size is large enough for estimating the population mean from the sample mean and the population standard deviation from the sample standard deviation.

So,

$\mu_{\bar x}=\bar x=13.65\\SE=\frac{s}{\sqrt{n}}=\frac{1.91}{\sqrt{100}}=0.191$

(a)

The null hypothesis is:

H₀: The usual load is 13 credits, i.e. μ = 13.

Assume that the significance level of the test is, α = 0.05.

Construct a (1 - α) % confidence interval for population mean to check the claim.

The (1 - α) % confidence interval for population mean is given by:

$CI=\bar x\pm z_{\alpha/2}\times SE$

For 5% level of significance the two tailed critical value of z is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Construct the 95% confidence interval as follows:

$CI=\bar x\pm z_{\alpha/2}\times SE\\=13.65\pm (1.96\times0.191)\\=13.65\pm0.3744\\=(13.2756, 14.0244)\\=(13.28, 14.02)$

As the null value, μ = 13 is not included in the 95% confidence interval the null hypothesis will be rejected.

Thus, it can be concluded that the usual load is not 13 credits.

(b)

Compute the probability that a a student at this college takes 16 or more credits as follows:

$P(X\geq 16)=P(\frac{X-\mu}{\sigma}\geq \frac{16-13.65}{1.91})\\=P(Z>1.23)\\=1-P(Z$

Thus, the probability that a a student at this college takes 16 or more credits is 0.1093.

3 0

3 years ago

Read 2 more answers

Carl is making a garden that is twice as long as it is wide. he wants to cover 271

d1i1m1o1n [39]

x²/2 =271 represents the situation where taking length twice as breadth and area as 271 ft² .

Area of a figure is the amount of space acquired by the figure

Area of a rectangle=Length x breadth

length=x

breadth=x/2

Area of rectangular lawn=lxb

=x.x/2

But as per question,

Area=271 ft²

⇒x²/2=271 1

⇒x=23.28 ft²

Therefore, x²/2 =271 represents the situation where taking length twice as breadth and area as 271 ft² .Value of x i.e. length is 23.28 ft²

Learn more about area,

brainly.com/question/25292087

#SPJ10

6 0

2 years ago

What is 31 billion in scientific notation?

zepelin [54]

Answer:

(3.10 x 10^10)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers