Answer:
Three friends buy 3 tickets and get one free
so , total cost = 6.15 × 3 = 18.45£
hence cost for one ticket = 18.45 / 4 = 4.61£
If you want to find the solutions for this you have to factor it. Since it's a second degree polynomial, you'll have 2 solutions. Factoring this using the quadratic formula, you'll get factors of (5x-8)(3x-4). Solving these for x you get x = 8/5 and x = 4/3.
![\bf Px+35=-6x+Q\implies \stackrel{P}{~~\begin{matrix} -6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}x+35=~~\begin{matrix} -6x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+\stackrel{Q}{35}\implies 35=35](https://tex.z-dn.net/?f=%5Cbf%20Px%2B35%3D-6x%2BQ%5Cimplies%20%5Cstackrel%7BP%7D%7B~~%5Cbegin%7Bmatrix%7D%20-6%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D%7Dx%2B35%3D~~%5Cbegin%7Bmatrix%7D%20-6x%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%2B%5Cstackrel%7BQ%7D%7B35%7D%5Cimplies%2035%3D35)
whenever you get an equality like so, that's a flat that both equations are exactly one and the same and thus the system has "infinitely many solutions".
<em>Greetings from Brasil...</em>
Before comparing mixed fractions, let's make them inappropriate
2 1/2 = 5/2
3 1/3 = 10/3
Comparing fractions. (MMC - Maximum Common Multiple -<em> I don't know that term in English</em>)
2 1/2 = 5/2 = 15/6
3 1/3 = 10/3 = 30/6
30/6 > 15/6 then
<h2>
3 1/3 > 2 1/2</h2>
<span>(x-3)(x^2+9)
or
x^3 -3x^2 + 9x - 27
First, let's see about factoring x^4 - 81. Cursory examination indicates that it's the difference of two squares and so it initially factors into
(x^2 - 9)(x^2 + 9)
And the (x^2 - 9) term is also the difference of 2 squares so it too factors into:
(x - 3)(x + 3)
So a partial factorization of x^4 - 81 is:
(x - 3)(x + 3)(x^2 + 9)
The (x^2 + 9) term could be factored as well, but that's not needed for this problem, and so I won't do it.
Now we can divide (x-3)(x+3)(x^2+9) by (x+3). The (x+3) terms will cancel and we get as the result
(x-3)(x+3)(x^2+9) / (x+3) = (x-3)(x^2+9)
We can leave the answer as (x-3)(x^2+9), or we can multiply it out, getting:
x^3 -3x^2 + 9x - 27</span>
