3. Both are supplementary to angle BCE
4. Angle 2 = Angle 1
Vertex is directly in middle of directix and focus
distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice
it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2
The answers to that problem vary which one came fiat
Answer:
(9/2)√x.
Step-by-step explanation:
Convert the radical to an exponent.
x√x = x^1 * x^1/2
= x^(1 + 1/2)
= x^3/2
So the derivative of 3x^3/2 is found as follows:
y' = 3 * 3/2x^(3/2 - 1)
= (9/2)x^1/2
= (9/2)√x.
