The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
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Answer:
The product will always be less than the factor.
Step-by-step explanation:
When you multiply numbers less than 1, you get a smaller factor each time.
-x + y = 4
2x+3y= 2
-2x + 2y = 8
2x + 3y = 2
5y = 10
y= 2
-x + 2 = 4
-x = 2
x = -2
Answer:
4(49v²+25)
Step-by-step explanation:


Answer:
T(-10, 7) U(-3, 7) V(-3,10) W(-10,10)
Step-by-step explanation:
I'm not 100% but I'm 90% sure I think all you have to do is flip the y to x and the x to the y value. Pls tell me if it is right??