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4 years ago

What is transportation?

Chemistry

2 answers:

Mandarinka [93]4 years ago

3 0

Movement from place to palce

SVEN [57.7K]4 years ago

3 0

It is moving place to place such as using a car train boat airplane or even just walking

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What is a rule you can use to predict the shape of a molecule based on the number of atoms and line electron pairs (i.e., substi

Alex17521 [72]

Answer:

VSEPR PRINCIPLE

Explanation:

I did some research and that was what I found, I hope this helps.

6 0

3 years ago

How many milliliters of a 0.80 M sucrose solution contain each of the following number of grams? The molar mass of sucrose (C12H

OlgaM077 [116]

The number of Ml of 0.80 M sucrose solution that contain

(A) 7.45 g are 27.25 Ml

<u>calculation</u>

volume= moles /molarity

molarity = 0.80 M which is the same as 0.80 mol/l

moles= mass/molar mass

= 7.45 g/ 342.3 g/mol =0.0218 moles

volume is therefore = 0.0218 moles / 0.80 mol/L=0.02725 L

convert into ml by multiplying by 1000

= 27.25 ml

<h3> <u> question b</u></h3>

volume = moles/molarity

molarity = 0.80 M = 0.80 Mol/L

moles =mass/molar mass

mass 17.0 mg convert into g by diving by 1000=0.017 g

moles is therefore = 0.017 g/ 342.3 g/mol = 4.97 x10^-5 moles

volume = (4.97 x 10^-5 moles) /0.8 mol /l=6.21 x10^-5 L

= 6.21 x10^-5 x 1000 =0.0621 Ml

7 0

4 years ago

The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests tha

lakkis [162]

Answer:

0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.

Explanation:

Volume of the radiator = 3.6 L

Percentage of antifreeze = 60%

Total volume of anti freeze in radiator = 60% of 3.6 L :

$\frac{60}{100}\times 3.6 = 2.16 L$

Percentage of water= 40%

Given,optimal cooling of the engine is obtained with only 50% antifreeze.

So, now we want to reduce the percentage of antifreeze from 60% to 50 %

Volume of coolant removed = x

Volume of water added = x

Volume of anti freeze removed = 60% of(x) = 0.6x

Volume of antifreeze left in radiator =50% of 3.6 L = $\frac{50}{100}\times 3.6=1.8 L$

1.8 Liter is the desired volume of the antifreeze.

Total volume - Removed volume = desired volume

2.16 L - 60% of( x) = 1.8 L

$2.16 L-0.6x=1.8 L$

$x=\frac{2.16 l- 1.8 L}{0.6}=0.6 L$

0.6 Liters of coolant should be drained and 0.6 Liter of water should be added.

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4 years ago

Which statement correctly describes a feature of the rock cycle?

sergejj [24]

Answer:

sediment can only form by weathering, erosion, and deposition

3 0

4 years ago

Read 2 more answers

I need help for this question

sesenic [268]

Answer:

Blanced

Explanation:

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3 years ago