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kherson [118]
3 years ago
10

Cuántos moles hay en 17.5 gramod de ZnCl2​

Chemistry
1 answer:
Aliun [14]3 years ago
4 0

Explanation:

Zn=65

Cl2= 35+35=70

65+70=135g

1 mole ZnCl2 = 135g

x mole = 17.5g

17.5g × 1 mole/ 135g= 0.129 moles en 17.5g de ZnCl2

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