All categories

2 years ago

If you want to conduct a practical study that finds

Mathematics

1 answer:

Aleks [24]2 years ago

8 0

Answer:

• Random sampling [ Probability and statistics method ]

Step-by-step explanation:

• This method is easier and saves time.

By probability, a person whose height is to be recorded will be chosen randomly. This will be done on approximately 40% members.

By statistical step, we'll feed results into distribution table. Then we'll find the mean height.

${ \boxed{ \rm{mean \: height = \frac{ \sum \: f(n)}{n} }}}$

• f of n is product of frequency and respective height bracket

• n is the number of samples.

You might be interested in

9.6x10^85/3x10^63 in scientific notation

Novosadov [1.4K]

Answer:

3.27*10^22

Step-by-step explanation:

Given the expression 9.6x10^85/3x10^63, we are to write it on scientific notation as shown:

9.6x10^85/3x10^63

= (9.8/3) * (10^85/10^63)

= (9.8/3) * 10^{85-63}

= (9.8/3) *10^22

= 3.27 *10^22

Hence the expression in scientific notation is 3.27*10^22

6 0

3 years ago

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

3 years ago

Use the model to complete the number sentence 1/2

VladimirAG [237]

That is one half also 1/2 if this was not what u where looking for then just tell me

8 0

3 years ago

2. A park ranger is standing on the top of a 125m hill looking down at a tree. She measuring the

Orlov [11]

Answer:

Step-by-step explanation:

hope this helps

4 0

3 years ago

-8 ( y + 4 ) = 10y + 4

maks197457 [2]

Let's solve your equation step-by-step.−8(y+4)=10y+4

Step 1: Simplify both sides of the equation.−8(y+4)=10y+4

Simplify: (−8)(y)+(−8)(4)=10y+4(Distribute)−8y+−32=10y+4−8y−32=10y+4

Step 2: Subtract 10y from both sides.−8y−32−10y=10y+4−10y−18y−32=4

Step 3: Add 32 to both sides.−18y−32+32=4+32−18y=36

Step 4: Divide both sides by -18.−18y−18=36−18y=−2

Answer:y=−2

Good luck mate :P

7 0

3 years ago

Read 2 more answers