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Genrish500 [490]
2 years ago
5

If you want to conduct a practical study that finds

Mathematics
1 answer:
Aleks [24]2 years ago
8 0

Answer:

• Random sampling [ Probability and statistics method ]

Step-by-step explanation:

• This method is easier and saves time.

By probability, a person whose height is to be recorded will be chosen randomly. This will be done on approximately 40% members.

By statistical step, we'll feed results into distribution table. Then we'll find the mean height.

{ \boxed{ \rm{mean \: height =  \frac{ \sum \: f(n)}{n} }}}

• f of n is product of frequency and respective height bracket

• n is the number of samples.

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9.6x10^85/3x10^63 in scientific notation
Novosadov [1.4K]

Answer:

<em>3.27*10^22</em>

Step-by-step explanation:

Given the expression 9.6x10^85/3x10^63, we are to write it on scientific notation as shown:

9.6x10^85/3x10^63

= (9.8/3) * (10^85/10^63)

= (9.8/3)  * 10^{85-63}

= (9.8/3) *10^22

= 3.27 *10^22

<em>Hence the expression in scientific notation is  3.27*10^22</em>

6 0
3 years ago
Find the 2th term of the expansion of (a-b)^4.​
vladimir1956 [14]

The second term of the expansion is -4a^3b.

Solution:

Given expression:

(a-b)^4

To find the second term of the expansion.

(a-b)^4

Using Binomial theorem,

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here, a = a and b = –b

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

Substitute i = 0, we get

$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4

Substitute i = 1, we get

$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b

Substitute i = 2, we get

$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}

Substitute i = 3, we get

$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}

Substitute i = 4, we get

$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}

Therefore,

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}

Hence the second term of the expansion is -4a^3b.

3 0
3 years ago
Use the model to complete the number sentence 1/2
VladimirAG [237]
That is one half also 1/2 if this was not what u where looking for then just tell me

8 0
3 years ago
2. A park ranger is standing on the top of a 125m hill looking down at a tree. She measuring the
Orlov [11]

Answer:

Step-by-step explanation:

hope this helps

4 0
3 years ago
-8 ( y + 4 ) = 10y + 4
maks197457 [2]
Let's solve your equation step-by-step.<span><span>−<span>8<span>(<span>y+4</span>)</span></span></span>=<span><span>10y</span>+4

</span></span>Step 1: Simplify both sides of the equation.<span><span>−<span>8<span>(<span>y+4</span>)</span></span></span>=<span><span>10y</span>+4

</span></span><span>Simplify: </span><span><span><span><span>(<span>−8</span>)</span><span>(y)</span></span>+<span><span>(<span>−8</span>)</span><span>(4)</span></span></span>=<span><span>10y</span>+4</span></span>(Distribute)<span><span><span><span>−<span>8y</span></span>+</span>−32</span>=<span><span>10y</span>+4</span></span><span><span><span>−<span>8y</span></span>−32</span>=<span><span>10y</span>+4

</span></span>Step 2: Subtract 10y from both sides.<span><span><span><span>−<span>8y</span></span>−32</span>−<span>10y</span></span>=<span><span><span>10y</span>+4</span>−<span>10y</span></span></span><span><span><span>−<span>18y</span></span>−32</span>=4

</span>Step 3: Add 32 to both sides.<span><span><span><span>−<span>18y</span></span>−32</span>+32</span>=<span>4+32</span></span><span><span>−<span>18y</span></span>=36

</span>Step 4: Divide both sides by -18.<span><span><span>−<span>18y</span></span><span>−18</span></span>=<span>36<span>−18</span></span></span><span>y=<span>−2

</span></span>Answer:<span>y=<span>−<span>2

Good luck mate :P
</span></span></span>
7 0
3 years ago
Read 2 more answers
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