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2 years ago

What am I suppose to do here? What is High range and Low range?

Mathematics

2 answers:

VLD [36.1K]2 years ago

7 0

That means what is the least u would spend and most so like if someone asked you how much you would pay for a product, you may say $7-$10 and 7 would be the low range and 10
would be the high range

Deffense [45]2 years ago

6 0

Answer:

Assuming that you will need all the amounts in high range, the total budget is = $2,046.45 + 877.05 + 877.05 + 1169.40 + 1169.40 + 409.29 + 877.05 = 7425.69.

Multiply the net monthly pay by the % of monthly income of each item.

Step-by-step explanation:

look at the pictures

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A.Find the total and area of the compound figures

goldfiish [28.3K]

Answer:

(a) The total area of compound figure is $284.52ft^2$ .

(b) The total perimeter of compound figure is 68.84 ft.

Step-by-step explanation:

Perimeter: The total distance covered by the figure.

Area: It is defined as the space occupied by the figure.

Given:

Length of rectangular figure = 19 ft

Breadth of rectangular figure = 12 ft

Radius of circle, r = $\frac{12ft}{2} = 6 ft$

Part (a):

Now calculating the total area of the compound figure.

$\text{Total area}=\text{Area of rectangular figure}+\frac{1}{2}\times \text{Area of circle}\\\\\text{Total area}=\text{Length}\times \text{Breadth}+\frac{1}{2}\times \pi r^2$

Now putting all the given values in this formula, we get:

$\text{Total area}=(19ft\times 12ft)+\frac{1}{2}\times 3.14\times (6ft)^2\\\\\text{Total area}=284.52ft^2$

Part (b):

Now calculating the total perimeter of the compound figure.

$\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times \text{Circumference})\\\\\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)$

Now putting all the given values in this formula, we get:

$\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)\\\\\text{Total perimeter}=2\times 19ft+12ft+(\frac{1}{2}\times 2\times 3.14 \times 6ft)\\\\\text{Total perimeter}=68.84ft$

8 0

3 years ago

For 10-18, Determine whether the triangles can be proved

navik [9.2K]

Answer:

180 - 92 - 41 = 47

There are not two similar congruent angle in the triangles.

Hope this helps!

3 0

2 years ago

Question 1) Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

USPshnik [31]

Question 1)

Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

F(G(x)) = 3(2x - 3)^2 + 1

F(G(x)) =3(4x^2 - 12x + 9) + 1

F(G(x)) = 12x^2 - 36x + 27 + 1

F(G(x)) =12x^2 - 36x + 28

Question 2)

Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x

H -1 (x) = x (inverse)

8 0

3 years ago

(x,-4) and (2,8): m = -3 find the missing value. it is in slope formula.

Snezhnost [94]

Answer:

The value of x = 6

Step-by-step explanation:

Given

The point (x,-4)

The point (2,8)

To determine

m = -3

Using the formula

Slope = m = [y₂ - y₁] / [x₂ - x₁]

here:

(x₁, y₁) = (x, -4)

(x₂, y₂) = (2, 8)

m = -3

so substitute (x₁, y₁) = (x, -4) , (x₂, y₂) = (2, 8) and m = -3

m = [y₂ - y₁] / [x₂ - x₁]

-3 = [8 - (-4)] / [2 - x]

-3 = [12] / [2-x]

-3 (2-x) = 12

-6+3x = 12

3x = 12+6

3x = 18

divide both sides by 3

3x/3 = 18/3

x = 6

Therefore, the value of x = 6

7 0

3 years ago

M(-5, 2) and N(5, 2) are the endpoints of the segment MN on the coordinate plane. What is the length of ?

VikaD [51]

The line segment is 10 units long

6 0

3 years ago

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