13m-22=9m-6
13m-9m-22=-6
4m-22=-6
4m=-6+22
4m=16
m=16/4
m=4
<em>Therefore, m is 4</em>
Now I am not sure what length you're supposed to find for problem 9, but x = 3.3 i think.
10.)
(14+x)+(x+21) = 13
2x+35=13
2x = -22
x = -11
FE = -11 + 14 = 3 units
11.)
10 + 2x - 10 = 3x - 8
2x = 3x - 8
-x = -8
x = 8
10 + 2(8) -10 = 16 units
Answer:the greatest number of pieces that can be cut is 2
Step-by-step explanation:
The total length of ribbon available is 3/4 meter. Sunday needs pieces measuring 1/3 meter for their project. This means that each length needed would be exactly 1/3 meter.
The number of pieces measuring 1/3 meter that can be cut from the ribbon would be
(3/4)/(1/3) = 3/4×3/1 = 9/4 = 2.25
Since the length needed is exactly 1/3 meter, the greatest number of pieces that can be cut will be 2
A rhombus would answer your question. Hope this helped sorry if im wrong.
A is the answer as (-4,8), (2,6), and many others are also possible solutions.
