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kirill115 [55]
2 years ago
7

At a basketball game, a vendor sold a combined total of 142 sodas and hot dogs. The number of sodas sold was 38 more than the nu

mber of hot dogs sold. Find the number of sodas sold and the number of hot dogs sold
Mathematics
1 answer:
kow [346]2 years ago
8 0
X represents the number of sodas
y represents the number of hot dogs

142 = x + y
x = 38 + y

Substitute x in the first equation

142 = 38 + y +y
142 - 38 = 2y
104/2 = 2y/2
y =52

x = 38 + 52
x = 90
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Secant jkl and jmn are drawn to circle o from an external point ,j. if jk=8,lk=4 and jm=6 what is the length of jn answer
Archy [21]
See the picture attached to better understand the problem

we know that
If two secant segments are drawn to a <span>circle </span><span>from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
</span>so
jl*jk=jn*jm------> jn=jl*jk/jm

we have
<span>jk=8,lk=4 and jm=6
</span>jl=8+4----> 12

jn=jl*jk/jm-----> jn=12*8/6----> jn=16

the answer is
jn=16

6 0
3 years ago
rebekah's baby brother weighs 7.71 pounds.How much will her baby brother weigh if he gains 1.3 pounds each week for two weeks?
NemiM [27]

Answer:

10.31 pounds

Step-by-step explanation:

First, we multiply 1.3 x 2 because he is gaining 1.3 for the next TWO weeks.

1.3 x 2 = 2.6

Now, add 7.71 + 2.6 because that is the weight he started with.

7.71 + 2.6 = 10.31‬

Her brother will weight 10.31 pounds if he is 7.71 lbs and continues to gain 1.3 pounds each week for two weeks.

8 0
3 years ago
The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All
Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

Pr(A)=\dfrac{11}{36} - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.

4 0
3 years ago
What is this answer?
Bumek [7]

Answer:

multiply

Step-by-step explanation:

just multiply all of them and then u will get your answer I hope this helped ❤

4 0
3 years ago
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Valentin [98]

Answer:

the answer is 9/2 therfore im just trying to get more words in

8 0
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