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FrozenT [24]
2 years ago
13

________ is the amount of data that can be transmitted across a transmission medium measured in bits per second.

Business
1 answer:
galben [10]2 years ago
7 0

Answer- Bandwidth

Explanation:

i looked up ur question so im not sure if its correct

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If a consumer buys Charmin bath tissue that is the exact same quality as a generic brand only more expensive, Charmin has create
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7 0
1 year ago
Consider the following information for three stocks, A, B, and C. The stocks' returns are positively but not perfectly positivel
Dmitry_Shevchenko [17]

Answer:

a) Portfolio ABC's expected return is 10.66667%

Explanation:

The expected return is based on the risk factor of a project. If a project has higher risk its rate of return will be higher. Portfolio ABC has one third of its funds invested in each stock. The return of on A and B are 20% and 10%. Their beta is 1.0 for both the stocks while stock C has beta 1.4. The portfolio expected return will be 10.66667%.

5 0
3 years ago
Granite State Airlines serves the route between New York and Portsmouth, NH, with a single-flight-daily 100-seat aircraft. The o
TEA [102]

Answer:

Given data: One flight with total seats = 100

Full fare passengers, cost per ticket=$150, mean=56 passengers, SD=23

Discount fare passengers, cost per ticket=$100, mean=88 passengers, SD=44

(a) Here, though there is a hint to use the CDF, since the confidence interval is not given we will make some simplying assumptions that will reduce the complexity of the question, of course keeping the question statistically correct.

this question wants us to maximize total revenue per flight (one way), we can do that by taking only full fare passengers or total revenue will be 150*100=$15,000, but since historical probability shows a mean of 56 with a standard deviation of 23, we can assume in best case scenario total full fare ticket passengers will be 56+23=79, leaving 21 tickets for discount passenger, in this case the total revenues will be 79*150+21*100=$13,950

(b) Now, the new constrained policy is giving a clear cut number of seats to each category of pasengers, 44 for discount (total revenues 44*100) and 56 for full fare (total revenues 56*150) both of which are within the probabilities given earlier (full fare mean=56, discount mean=88). Total revenues in case will be 44*100+56*150=$12,800.

(c) Gain is the difference of the excess revenues in both cases of optimal total revenues and limited seats policy or answer (a) - answer (b) = $13,950- $12,800=$1,150

(d) Realistically speaking, there is no answer for this question without a clear cut confidence interval. Another simplifying assumption we can make here is taking the mean passengers as expected bookings (can be tweaked once confidence interval or degree of significance is given). so total revenues in this case will be 44*100 from discount and 56*150 from full fare passengers. That is still similar to answer (c) due to our assumption/lack of constraints, so our optimal booking will be 54 full fare tickets and 44 discount passenger tickets. You can also take worst case scenario by subtracting SD of each passenger type from the mean or go the best case scenario in which SD of full fare will be added to the mean while the pending seats (left over from 100) will be the total to discount fare for optimal revenue collection.

6 0
3 years ago
Read 2 more answers
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