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2 years ago

What should be added to the answer of 54 X 34 to get the answer of 58 X 34 ?

2 answers:

7 0

It's impossible. All the numbers in the list are just 2∗
2
∗
(odd number) from 1 to 29.

Now, add up any three of them. Let's say the 3 odd numbers you choose are ,,
a
,
b
,
c

So, 2a + 2b + 2c = 60

2(a + b + c) = 2(30)

But, since a, b and c are all odd, their sum must always be an odd number. Why? Because:

odd + odd + odd = (odd + odd) + odd

= even + odd = odd

Since 3 odd numbers always add up to another odd number, their sum cannot be 30. Thus, it is not possible to add three of those numbers to give you 60, or any number divisible by 4

zalisa [80]2 years ago

4 0

You multiply the number then divide by 2 or just keep it the same answer

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Factorise: a^2 + 8a - 20

REY [17]

Which two numbers add up to 88 and multiply to −20?
−2 and 10

Rewrite the expression using the above:

Answer:
(a−2)(a+10)

6 0

3 years ago

Read 2 more answers

When will the equation xn = c, where c is a whole number, have two solutions? Explain.

Kazeer [188]

If x=n then it would have 2 solutions because it would be x^2 = c which has a positive and negative solution but idk if that is what you are asking for

3 0

3 years ago

Regina brought 8 7/8 pound of fruit for her family . She brought 3 1/2 pound of oranges and 2 3/4 pound of peaches and some appl

butalik [34]

Answer:

Regina has bought $2\frac{5}{8}\ pounds$ of apples.

Step-by-step explanation:

Given:

Amount of fruit brought = $8\frac{7}{8}\ pounds$

Now given number is in mixed fraction we will convert into improper fraction.

To convert a mixed fraction to an improper fraction, we will Multiply the whole number part by the fraction's denominator. Add that to the numerator,Then write the result on top of the denominator.

So we can say that;

$8\frac{7}{8}\ pounds$ can be Rewritten as $\frac{71}{8}\ pounds$

Amount of fruit brought = $\frac{71}{8}\ pounds$

Also given:

Amount of oranges bought = $3\frac12\ pounds$

$3\frac12\ pounds$ can be Rewritten as $\frac{7}{2}\ pounds$

Amount of oranges bought = $\frac{7}{2}\ pounds$

Amount of peaches bought = $2 \frac34\ pounds$

$2 \frac34\ pounds$ can be Rewritten as $\frac{11}{4}\ pounds$

Amount of peaches bought = $\frac{11}{4}\ pounds$

We need to find amount of apples bought by Regina.

Solution:

Let the amount of apples bought be 'x'

Now we know that;

Amount of fruit brought is equal to sum of Amount of oranges bought and Amount of peaches bought amount of apples.

framing in equation form we get;

$\frac{71}{8}=\frac{7}{2}+\frac{11}{4}+x\\\\x=\frac{71}{8}-\frac{7}{2}-\frac{11}{4}$

Now we will make the denominator common using LCM we get.

$x=\frac{71\times 1}{8\times 1}-\frac{7\times4}{2\times4}-\frac{11\times2}{4\times2}\\\\x=\frac{71}{8}-\frac{28}{8}-\frac{22}{8}$

Now denominators are same so we will solve the numerator.

$x=\frac{71-28-22}{8}\\\\x=\frac{21}{8}\ pounds$

Now $\frac{21}{8}\ pounds$ can be Rewritten as $2\frac{5}{8}\ pounds$

Hence Regina has bought $2\frac{5}{8}\ pounds$ of apples.

5 0

3 years ago

Solve for x write the exact answer using either base -10 or base-e logarithms

jeka57 [31]

Given:

The given expression is $2^{x+5}=13^{2 x}$

We need to determine the value of x using either base - 10 or base - e logarithms.

Value of x:

Let us determine the value of x using the base - e logarithms.

Applying the log rule that if $f(x)=g(x)$ then $\ln (f(x))=\ln (g(x))$

Thus, we get;

$\ln \left(2^{x+5}\right)=\ln \left(13^{2 x}\right)$

Applying the log rule, $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$ , we get;

$(x+5) \ln (2)=2 x \ln (13)$

Expanding, we get;

$x \ln (2)+5 \ln (2)=2 x \ln (13)$

Subtracting both sides by $5 \ln (2)$ , we get;

$x \ln (2)=2 x \ln (13)-5 \ln (2)$

Subtracting both sides by $2 x \ln (13)$ , we get;

$x \ln (2)-2 x \ln (13)=-5 \ln (2)$

Taking out the common term x, we have;

$x( \ln (2)-2 \ln (13))=-5 \ln (2)$

$x=\frac{-5 \ln (2)}{\ln (2)-2 \ln (13)}$

$x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

Thus, the value of x is $x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

6 0

3 years ago

13. A school is planning an excursion for all of their students to see the

Roman55 [17]

Answer:

Please Explain

Step-by-step explanation:

13. A school is planning an excursion for all of their students to see the

penguins on Phillip Island. They find a company who can provide

two different types of coaches for the trip: one that holds 34

passengers and one that holds 51 passengers. The coach company

has 8 of the smaller coaches and 4 larger coaches available.

The hire cost $500 for a smaller coach and $700 for a larger coach.

If there are 374 students and teachers going on the trip,

determine the minimum total cost for the coach hire.

5 0

3 years ago