Answer:
The correct option is;
comparing plant survivorship in areas where hikers stay on the trail with plants where hikers leave the trail
Step-by-step explanation:
The hypothesis that the area formerly covered by known plants which is now bare soil due to trampling in the alpine areas by hikers can be tested by means of comparing the areas where during the cause of their visit, the hikers remain on the trail as they move within the park to other portion of the park where it is known that there are either very few or no hiker remain on the trail. The outcome will determine if the cause of the appearance of bare soil is due to the transit and trampling by hikers.
3x + 2y + y - 3x = 180
3y = 180
y = 180/3
y = 60
3x = y - 3x
Let y = 60
3x = 60 - 3x
3x + 3x = 60
6x = 60
x = 60/6
x = 10
Answer: x = 10, y = 60
Answer:
a) Bar chart
b) Histogram
c) Bar chart
d) Histogram
Step-by-step explanation:
a) Trash pick-up DAY for each HOUSEHOLD in Ames - This is categorical data because, we are talking about days of the week. For instance, Household 1 might have Sunday as Trash pick-up day and that could be accumulated into frequency. Hence, BAR chart is the most appropriate.
b) Patient WAIT-TIME at ISU. This is continuous (quantitative) data. And the most appropriate is HISTOGRAM.
c) Number of trips taken during a GIVEN SCHOOL YEAR by EACH ISU STUDENT. Let say we have 5 ISU STUDENTS. Student 1 had 5 trips, student 2 had 10 trips, etc.
We want to see which student has the most and least trip in that particular school year. Although is count data but the most appropriate graphical display is BAR chart.
d) TAX BRACKET of ALL Iowa RESIDENTS. This is a continuous (quantitative) data. The most appropriate graphical display is HISTOGRAM.
Answer:
2.8
Step-by-step explanation:
1 Expand
1.4t-0.4t+1.24=5.8
2 Simplify 1.4t-0.4t+1.241.4t−0.4t+1.24 to t+1.24t+1.24
t+1.24=5.8
3 Subtract 1.241.24 from both sides
t=5.8−1.24
4 Simplify 5.8-1.245.8−1.24 to 4.564.56
t=4.56
