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Colt1911 [192]
3 years ago
13

A regular pentagon has a perimeter of 40cm what is the measure of each interior angle.

Mathematics
2 answers:
Vika [28.1K]3 years ago
8 0

Answer:

8 because you have to divide 40 by 5 and it will get you to 8

docker41 [41]3 years ago
5 0
The answer is 8
Hope this helps
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A function of random variables used to estimate a parameter of a distribution is a/an _____.
stiks02 [169]

A function of random variables utilized to calculate a parameter of distribution exists as an unbiased estimator.

<h3>What are the parameters of a random variable?</h3>

A function of random variables utilized to calculate a parameter of distribution exists as an unbiased estimator.

An unbiased estimator exists in which the difference between the estimator and the population parameter grows smaller as the sample size grows larger. This simply indicates that an unbiased estimator catches the true population value of the parameter on average, this exists because the mean of its sampling distribution exists the truth.

Also, we comprehend that the bias of an estimator (b) that estimates a parameter (p) exists given by; E(b) - p

Therefore, an unbiased estimator exists as an estimator that contains an expected value that exists equivalent to the parameter i.e the value of its bias exists equivalent to zero.

Generally, in statistical analysis, the sample mean exists as an unbiased estimator of the population mean while the sample variance exists as an unbiased estimator of the population variance.

Therefore, the correct answer is an unbiased estimator.

To learn more about unbiased estimators refer to:

brainly.com/question/22777338

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4 0
1 year ago
What is the probability of drawing the compliment of a king or a
inna [77]

Answer:

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

n( E_{1} ) = 4 _{C_{1} }  = 4

Let E₂ be the event of the card drawn being a queen

n( E_{2} ) = 4 _{C_{1} }  = 4

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

<u><em>step(ii):-</em></u>

The probability  of drawing of a king or a  queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

                 = \frac{4}{52} + \frac{4}{52}

P( E₁ U E₂ ) = \frac{8}{52}

<u><em>step(iii):-</em></u>

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards

P(E_{1}UE_{2})  ^{-} = 1- P(E_{1} U E_{2} )

P(E_{1}UE_{2})  ^{-} = 1- \frac{8}{52}

P(E_{1}UE_{2})  ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846

<u><em>Conclusion</em></u>:-

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

5 0
3 years ago
The math club sells candy bars and drinks during football games.
8090 [49]
Divide 270 by 90 then the answer will be 3, so 1 candy bar is sold for $3
8 0
4 years ago
For the fair, the organizers ordered
zhannawk [14.2K]

Each roll of tickets = 100 tickets

32 * 100 = 3200

3,200 tickets were ordered in all.

5 0
4 years ago
Read 2 more answers
Simplify the equation. x/(x-4 )+ 4/(x-4 )
ANTONII [103]

Answer:

x+4/x-4

Step-by-step explanation:

=x/(x-4)+4/(x-4) [ l.c.m= (x-4)]

=x+4/x-4

6 0
3 years ago
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